Car X traveled 3d distance in t time. Car Y traveled 2d distance in t time. Therefore, the speed of car X, is 3d/t, the speed of car Y, is 2d/t. Since speed is the distance taken in a given time.
In figure-2, they are at the same place, we are asked to find car Y's position when car X is at line-A. We can calculate the time car X needs to travel to there. Let's say that car X reaches line-A in t' time.
Okay, it takes t time for car X to reach line-A. Let's see how far does car Y goes.
We found that car Y travels 2d distance. So, when car X reaches line-A, car Y is just a d distance behind car X.
Answer:
B) 3.50 m/s
Explanation:
The linear velocity in a circular motion is defined as:
The angular frequency (
) is defined as 2π times the frequency and r is the radius, that is, the distance from the center of the circular motion.
Replacing (2) in (1):
We have to convert the frequency to Hz:
Finally, we calculate how fast is the child moving:
Answer:
v = 14.32 m/s
Explanation:
According to the principle of conservation of linear momentum, both the momentum and kinetic energy of the system are conserved. Since the two balls are in the same direction of motion before collision, then;
+ 
= (
+ 
) v
0.035 × 12 + 0.120 × 15 = (0.035 + 0.120) v
0.420 + 1.800 = (0.155) v
2.22 = 0.155 v
⇒ v = 
= 14.323
The velocity of the balls after collision is 14.32 m/s.
The angle of baking from the calculation is obtained as 30°.
<h3>What is banking?</h3>
The term banking refers to a means of preventing vehicles from skidding off the road at curves.
We know that the banking angle is obtained from;
θ = tan-1(v^2/rg)
v = 24.5 m/s
r = 110 m
g = 9.8 m/s^2
θ = tan-1(25^2/9.8 * 110)
θ = tan-1(625 /1078)
θ = 30°
Learn more about the banking angle:brainly.com/question/26759099?r
#SPJ1
It acquires a charge through electrons.
Hope this helps!!!^_~!!!
