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frez [133]
4 years ago
5

You have a meter stick marked to the nearest millimeter. Which of these measurements is written with the correct amount of preci

sion? A. 1.1 m B. 1.11 m C. 1.001 m D. 1,011.1 m
Physics
2 answers:
victus00 [196]4 years ago
8 0

Answer:

1.001 m

Explanation:

We have to find the least measurement of the instrument.

In this case the least measurement = 1 mm

                                                           = (1/1000) m

                                                           = 0.001 m

The measurement that is precise from this instrument should be to the nearest thousandth when taken in meters.

Therefore the answer is: 1.001 m

matrenka [14]4 years ago
6 0

Answer:

c 1.001

Explanation:

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Physical
zysi [14]

Answer: 2.5

Explanation:

4 0
3 years ago
Unpolarized light passes through a vertical polarizing filter, emerging with an intensity I0. The light then passes through a ho
antiseptic1488 [7]

To solve this problem it is necessary to apply the concepts related to Malus' law. Malus' law indicates that the intensity of a linearly polarized ray of light that passes through a perfect analyzer with a vertical optical axis is equivalent to:

I = I_0 cos^2(\theta)

I_0 = Indicates the intensity of the light before passing through the Polarizer,

I = The resulting intensity, and

\theta = Indicates the angle between the axis of the analyzer and the polarization axis of the incident light.

There is 3 polarizer, then

For the exit of the first polarizer we have that the intensity is,

I_2 = I_0cos^2(45)

For the third polarizer then we have,

I_3 = I_2 cos^{2}(45)

Replacing with the first equation,

I_3 =  I_0cos^2(45)cos^{2}(45)

I_3 = I_0 (\frac{1}{2})(\frac{1}{2})

I_3 = I_0 \frac{1}{4}

Therefore the transmitted intensity now is \frac{1}{4} of the initial intensity.

5 0
4 years ago
A 860g block of titanium metal has a volume of 200 cm3 and the density of 4.3g/cm^3.
valina [46]

Answer:

4.3 g/ cm^3

Explanation:

Mass / Volume = density . so 2150/500= 4.3 g/cm^3

6 0
3 years ago
To tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.50•10^6 N, one at an angle 19.0° west of north, a
irina1246 [14]

Answer:

Work done by a tug boat, W = 1.735 x 10⁸ J

Explanation:

Given,

The of each tugboat, F = 1.5 x 10⁶ N

The angle of each tugboat forms with the resultant force, θ = 19°

The displacement of the supertanker, s = 710 m

The individual tugboat will be responsible for the displacement, d = 710/2

                                                                                                               = 355 m

The displacement component in each tugboat direction = 355 · sin θ meter

Therefore, the work done by each tugboat is

                                           W = F x S    joules

Substituting the values in the above equation

                                            W = 1.5 x 10⁶  x  355 · sin θ

                                                = 1.735 x 10⁸ J

Hence, the work done by each tugboat is, W = 1.735 x 10⁸ J                        

6 0
3 years ago
Tom Sawyer runs 10 m/s down the dock and leaps on to his floating raft already moving 1.5 m/s away from shore. If Tom weighs 70
KatRina [158]

Answer:

Not the right answer in the options, speed is 4.47 m/s, and the procedure is coherent with option A

Explanation:

Answer A uses mass and velocity units, which are momentum units. By using the conservation of momentum:

.p_{initial} =p_{final} \\m_{Tom}*v_{Tom}+m_{raft}*v_{raft}=(m_{Tom}+m_{raft})*v_{both} \\70*10+130*1.5 kg*m/s=895kg*m/s\\v_{both}=\frac{895 kg*m/s}{200 kg} =4.47 m/s

Since Tom stays in the raft, then both are moving with the same speed. From the options, the momentum is in agreement with option A, however, the question asks for speed.

3 0
3 years ago
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