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3 years ago

What is the complete ionic equation for NaOHaq plus HCIaq equals H2OI plus NaCIaq?

Chemistry

1 answer:

OverLord2011 [107]3 years ago

3 0

Answer:

Ionic equation:

Na⁺(aq) + OH⁻(aq) + H⁺(aq) + Cl⁻(aq) → H₂O(l) + Na⁺(aq) + Cl⁻ (aq)

Explanation:

Chemical equation:

NaOH(aq) + HCl(aq) → H₂O(l) + NaCl (aq)

Balanced chemical equation:

NaOH(aq) + HCl(aq) → H₂O(l) + NaCl (aq)

Ionic equation:

Na⁺(aq) + OH⁻(aq) + H⁺(aq) + Cl⁻(aq) → H₂O(l) + Na⁺(aq) + Cl⁻ (aq)

Net ionic equation:

OH⁻(aq) + H⁺(aq) → H₂O(l)

The Cl⁻(aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.

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How many moles of ethanol, C2H5OH, are in a sample which weighs 39.2 g? (Hint: your answer needs to be less than the 1 mole b/c

m_a_m_a [10]

Answer:

Explanation:

To find how many moles are in the sample, you first must calculate how much one mole of C2H5OH weighs.

2(mass of C) + 5(mass of H) + (mass of O) + (mass of H)

= 2(12.01) + 5(1.008) + (16.00) + (1.008) = 46.068 g/mol

So, now that we know what 1 mole weighs, we can simply divide the weight of the sample by the weight of a mole of ethanol to get our answer.

39.2 / 46.068 = approximately 0.851 mol of ethanol

7 0

3 years ago

Which reaction most accurately represents the dissociation of nitrous acid (hno2) in water?

yanalaym [24]

When nitrous acid (HNO₂) dissociates in water (H₂O), the reaction that best captures this process is:

HNO₂ (aq.) + H₂O ↔ H₃O⁺ (aq.) + NO₂⁻ (aq.)

How does one know about HNO₂?

The chemical designation for nitrous acid is HNO₂, and it is a monoprotic acid. Three elements—hydrogen(H), oxygen(O), and nitrogen(N), all compose it.
It is highly fragile in nature and only occurs in solutions.
It is employed to convert amines into diazonium salts.

Is HNO₂ a basic or an acid?

Acidity is assigned to nitrous acid (HNO₂). Once dissolved in water, it gives out H+ ions. Acid is a chemical that produces H+ ions in a water-based solution or gives the protons to other molecules.

Thus, HNO₂ is acid because it causes a mixture of water to contain H+ ions. In a 10 mM concentration, it possesses a pH of 2.67.

Learn more about nitrous acid here:

brainly.com/question/17055219

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8 0

2 years ago

Plutonium−239 (t1/2 = 2.41 × 104 yr) represents a serious nuclear waste hazard. if seven half-lives are required to reach a tole

dimulka [17.4K]

The half-life of Plutonium−239, t1/2 is 2.41 × 10⁴<span> yrs

time taken to reach tolerable level = seven half-lives
= 7 x t1/2
= 7 x </span>2.41 × 10⁴ yrs
= 168700 yrs
= 1.687 x 10⁵ yrs

Hence, the period of time that <span>Plutonium-239 must be stored is </span>1.687 x 10⁵ years.

5 0

3 years ago

Read 2 more answers

The density of gold is 19.3 g/cm³. What is the mass of 11.3 cm³ of gold?

telo118 [61]

Answer:

218.09g

Explanation:

the formula for density is mass/volume

you have volume so rlly what you have is 19.3g/cm3=m/11.3cm3

so mass equals density x volume

and 19.3 x 11.3 = 218.09

4 0

3 years ago

At 298 K, what is the Gibbs free energy change (ΔG) for the following reaction?

9966 [12]

Answer:

(a). The Gibbs free energy change is 2.895 kJ and its positive.

(b). The Gibbs free energy change is 34.59 J/mole

(c). The pressure is 14924 atm.

(d). The Gibbs free energy of diamond relative to graphite is 4912 J.

Explanation:

Given that,

Temperature = 298 K

Suppose, density of graphite is 2.25 g/cm³ and density of diamond is 3.51 g/cm³.

$\Delta H\ for\ diamond = 1.897 kJ/mol$

$\Delta H\ for\ graphite = 0 kJ/mol$

$\Delta S\ for\ diamond = 2.38 J/(K mol)$

$\Delta S\ for\ graphite = 5.73 J/(K mol)$

(a) We need to calculate the value of $\Delta G$ for diamond

Using formula of Gibbs free energy change

$\Delta G=\Delta H-T\Delta S$

Put the value into the formula

$\Delta G= (1897-0)-298\times(2.38-5.73)$

$\Delta G=2895.3$

$\Delta G=2.895\ kJ$

The Gibbs free energy change is positive.

(b). When it is compressed isothermally from 1 atm to 1000 atm

We need to calculate the change of Gibbs free energy of diamond

Using formula of gibbs free energy

$\Delta S=V\times\Delta P$

$\Delta S=\dfrac{m}{\rho}\times\Delta P$

Put the value into the formula

$\Delta S=\dfrac{12\times10^{-6}}{3.51}\times999\times10130$

$\Delta S=34.59\ J/mole$

(c). Assuming that graphite and diamond are incompressible

We need to calculate the pressure

Using formula of Gibbs free energy

$\beta= \Delta G_{g}+\Delta G+\Delta G_{d}$

$\beta=V(-\Delta P_{g})+\Delta G+V\Delta P_{d}$

$\beta=\Delta P(V_{d}-V_{g})+\Delta G$

Put the value into the formula

$0=\Delta P(\dfrac{12\times10^{-6}}{3.51}-\dfrac{12\times10^{-6}}{2.25})\times10130+2895.3$

$0=-0.0194\Delta P+2895.3$

$\Delta P=\dfrac{2895.3}{0.0194}$

$\Delta P=14924\ atm$

(d). Here, $C_{p}=0$

So, The value of $\Delta H$ and $\Delta S$ at 900 k will be equal at 298 K

We need to calculate the Gibbs free energy of diamond relative to graphite

Using formula of Gibbs free energy

$\Delta G=\Delta H-T\Delta S$

Put the value into the formula

$\Delta G=(1897-0)-900\times(2.38-5.73)$

$\Delta G=4912\ J$

Hence, (a). The Gibbs free energy change is 2.895 kJ and its positive.

(b). The Gibbs free energy change is 34.59 J/mole

(c). The pressure is 14924 atm.

(d). The Gibbs free energy of diamond relative to graphite is 4912 J.

7 0

3 years ago