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Reptile [31]
3 years ago
9

A ball traveling with an initial momentum of 4.5 kgm/s bounces off a wall and comes back in the opposite direction with a moment

um of –3.5 kgm/s. What is the change in momentum?
Physics
1 answer:
irinina [24]3 years ago
3 0

Answer:

-7.5 kg m/s

Explanation:

Initial momentum (p1) = 4.5 kg m/s

final momentum (p2) = -3.5 kg m/s

We have to find out the change in momentum , As linear momentum is a vector quantity. So, we have to use the vector form to solve the momentum change . Means we have to take the sign of momentum also.

Change in momentum = Final momentum - initial momentum

So,

Change in momentum = p2 - p1

Insert values from question,

Change in momentum = -3.5 kg m/s - 4 kg m/s

So, change in momentum = -7.5 kg m/s

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What is the relationship between air pressure and air temperature?
LenKa [72]
The relationship between the two is that air temperature changes the air pressure. For example, as the air warms up the molecules in the air become more active and they use up more individual space even though there is the same<span> number of molecules. This causes an </span>increase<span> in the air pressure.</span>
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4 years ago
A ball of mass 8 kg falls from rest from a height of 100 m. Neglecting air resistance,calculate its kinetic energy after falling
astra-53 [7]
As an object falls from rest, its gravitational energy is converted to kinetic energy

G.P.E = K.E = mgh

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4 0
4 years ago
Read 2 more answers
What is the equivalent resistance in this circuit?<br><br> What is the current in this circuit?
kramer

All these resistors are in series so we can take the sum of them by:

Rtotal = R1 + R2 + R3......

So...

Rtotal = 2 + 3 + 4 + 6

Rtotal = 15

So now the total resistance in the circuit is 15 ohms and the potential difference applied to the circuit is 45 volts

Now we can use:

V = IR

Isolate for I

V/R = I

45/15 = I

I = 3 amps (A)

3 0
4 years ago
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An organ pipe is made to play a low note at 27.5 Hz, the same as the lowest note on a piano. Assuming a sound speed of 343 m/s,
timama [110]

Answer:

The length of open-open pipe needed is 6.23 m

The length of open-close  pipe needed is 3.11 m

Explanation:

Fundamental frequency for standing wave mode of  an open- open pipe is given by

f=\frac{v}{2L}

where v is the velocity and L is the length

The length of open-open pipe needed is

L=\frac{v}{2f} \\L=\frac{343}{2\times 27.5} \\L=6.23 m

Fundamental frequency for standing wave mode of  an open- close pipe is given by

f=\frac{v}{2L}

The length of open-close pipe needed is

L=\frac{v}{2f} \\L=\frac{343}{2\times 27.5} \\L=6.23 m

7 0
3 years ago
100 kw of power is delivered to the other side of a city by a pair of power lines with the voltage difference of 13014.1 v.
FinnZ [79.3K]
A) The power delivered to the lines is
P_{in}= 100 kW=1 \cdot 10^5 W
And the voltage at which the lines work is
V=13014.1 V
Since the power delivered is the product between the voltage and the current:
P=VI
We can find the current flowing in the lines:
I= \frac{P}{V}= \frac{1 \cdot 10^5 W}{13014.1 V}=7.68 A

b) The voltage change along each line can be found by using Ohm's law:
\Delta V = IR = (7.68 A)(10 \Omega)=76.8 V

c) The power wasted as heat along each line is given by:
P_d = I^2 R = (7.68 A)^2 (10 \Omega) = 590 W
And since we have 2 lines, the total power wasted as heat in both lines is
P_d = 2 \cdot 590 W=1180 W
6 0
3 years ago
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