Answer:
<em>The ball falls 0.3 m in the first 1/4 seconds, and it falls 0.92 m in the second 1/4 second</em>
Explanation:
<u>Horizontal Launch
</u>
When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.
To calculate the vertical distance (y) traveled by the object in terms of the time (t) we use:

The fastball is thrown horizontally. The distance the ball falls in t=1/4 seconds = 0.25 seconds, is:


The distance the ball falls in t=1/2 seconds = 0.5 seconds is:


The distance it falls in the second 1/4 second is:


The ball falls 0.3 m in the first 1/4 seconds, and it falls 0.92 m in the second 1/4 second
Answer:
As we keep on increasing the radius the value of the gravitation force of attraction decreases and as we decrease the radius the gravitation force increases.
Explanation:
Like the coulombs law of electrostatics, the law of gravitation also depends inversely on the square of the value of r. Therefore, as we keep on increasing the value of r the value of the gravitation force decreases and as we decrease the value of the r the value of gravitation force increases.
Gravitation Force=
Coulombs's Law= 
About 5 billion years ago
Answer:
So percentage error will be 2 %
Explanation:
We have given initial value of acceleration due to gravity 
And final value of acceleration due to gravity 
We have to find the percentage error
We know that percentage error is given by 
So
%
Answer:
459.6J
Explanation:
Given parameters:
Angle of pull = 40°
Force applied = 30N
Distance moved = 20m
Unknown:
Work done by Kraig = ?
Solution:
To solve this problem;
Work done = F x dcosФ
d is the distance
F is the force
Ф is the angle given
Work done = 30 x 20cos40° = 459.6J