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2 years ago

What do you think are some of the most pressing environmental science issues

Chemistry

2 answers:

Nezavi [6.7K]2 years ago

6 0

Answer:

i believe global warming

trasher [3.6K]2 years ago

4 0

Floods,drought, fires, tornadoes,:)

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Do all metals have more electrons than protons

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Explanation:

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3 years ago

Which physical method can separate a mixture of steel ball bearings and marbles

Lana71 [14]

Sorting is a method that could separate those materials

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3 years ago

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Answer the amount of miles of O2

lord [1]

Answer:

Explanation:

the answer is 3 because it is 3 for the o2 so 3 you have to pay more attention for the small ditails

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1 year ago

Take a cup of water, add sugar, and stir. if the resulting solution contains sugar crystals that do not dissolve, the solution i

Strike441 [17]

When a solvent has as much of the dilute dissolved in it as possible, then it is saturated.

If you were to heat the water, its capacity would increase and would then be super-saturated because it has more dissolved in it than possible as room temp.

Since there is no heating being done, the water is just saturated.

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2 years ago

Calculate the molarity of sodium ion in a solution made

Arada [10]

Answer:

0.1035 M

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Sodium chloride will furnish Sodium ions as:

$NaCl\rightarrow Na^{+}+Cl^-$

Given :

For Sodium chloride :

Molarity = 0.288 M

Volume = 3.58 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 3.58×10⁻³ L

Thus, moles of Sodium furnished by Sodium chloride is same the moles of Sodium chloride as shown below:

$Moles =0.288 \times {3.58\times 10^{-3}}\ moles$

Moles of sodium ions by sodium chloride = 0.00103104 moles

Sodium sulfate will furnish Sodium ions as:

$Na_2SO_4\rightarrow 2Na^{+}+SO_4^{2-}$

Given :

For Sodium sulfate :

Molarity = 0.001 M

Volume = 6.51 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 6.51 ×10⁻³ L

Thus, moles of Sodium furnished by Sodium sulfate is twice the moles of Sodium sulfate as shown below:

$Moles =2\times 0.001 \times {6.51\times 10^{-3}}\ moles$

Moles of sodium ions by Sodium sulfate = 0.00001302 moles

Total moles = 0.00103104 moles + 0.00001302 moles = 0.00104406 moles

Total volume = 3.58 ×10⁻³ L + 6.51 ×10⁻³ L = 10.09 ×10⁻³ L

Concentration of sodium ions is:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity_{Na^+}=\frac{0.00104406}{10.09\times 10^{-3}}$

The final concentration of sodium anion = 0.1035 M

4 0

3 years ago