Answer:
D. 0.75 grams
Explanation:
The data given on the iridium 182 are;
The half life of the iridium 182,
= 15 years
The mass of the sample of iridium, N₀ = 3 grams
The amount left, N(t) after two half lives is given as follows;
![N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}} }](https://tex.z-dn.net/?f=N%28t%29%20%3D%20N_0%20%5Cleft%20%28%5Cdfrac%7B1%7D%7B2%7D%20%5Cright%20%29%5E%7B%5Cdfrac%7Bt%7D%7Bt_%7B1%2F2%7D%7D%20%7D)
For two half lives, t = 2 × ![t_{(1/2)}](https://tex.z-dn.net/?f=t_%7B%281%2F2%29%7D)
∴ t = 2 × 15 = 30
![\dfrac{t}{t_{(1/2)}} = \dfrac{30}{15} = 2](https://tex.z-dn.net/?f=%5Cdfrac%7Bt%7D%7Bt_%7B%281%2F2%29%7D%7D%20%3D%20%5Cdfrac%7B30%7D%7B15%7D%20%3D%202)
![\therefore N(t) = 3 \times\left (\dfrac{1}{2} \right )^2 = 0.75](https://tex.z-dn.net/?f=%5Ctherefore%20N%28t%29%20%3D%203%20%5Ctimes%5Cleft%20%28%5Cdfrac%7B1%7D%7B2%7D%20%5Cright%20%29%5E2%20%3D%200.75)
∴ The amount left, N(t) = 0.75 grams
Answer:
C.
The pan will be the same temperature as the stove.
Explanation:
- The independent variable (IV) is the lemon juice mixture
- The dependent variable (DV) is the appearance of the green slime on the shower
- The control variable (CV) are time taken to spray, the amount of spray
- The experimental group (EG) is the side of the shower sprayed with lemon juice mixture
- The control group (CG) is the side of the shower sprayed with water.
INDEPENDENT VARIABLE
- Independent variable is the variable of an experiment that is changed by the experimenter in order to bring about a change. It is the variable being tested in the experiment. In this case, the IV is the lemon juice mixture tested on the green slime on the shower.
DEPENDENT VARIABLE:
- Dependent variable is the variable that is observed or measured in an experiment. It is also called responding variable. The DV in this case is the appearance of the green slime on the shower.
CONTROL VARIABLE:
- Control variable is the variable that is kept constant throughout the experiment for all groups. The CV is the same for all the groups and they include: time taken to spray, the same amount of spray
CONTROL GROUP
- Control group is the group that does not receive the independent variable or test in an experiment. In this case, the CG is the side of the shower sprayed with water.
EXPERIMENTAL GROUP:
- Experimental group is the group of ab experiment that receives the experimental treatment or independent variable. In this case, the EG is the side of the shower sprayed with lemon juice mixture.
Therefore, the IV, DV, CV, EG and CG of this experiment are as follows:
- The independent variable (IV) is the lemon juice mixture
- The dependent variable (DV) is the appearance of the green slime on the shower
- The control variable (CV) are time taken to spray, the amount of spray
- The experimental group (EG) is the side of the shower sprayed with lemon juice mixture
- The control group (CG) is the side of the shower sprayed with water.
Learn more: brainly.com/question/17498238?referrer=searchResults
<u>Answer:</u> The true statement is iron can reduce
to gold metal
<u>Explanation:</u>
Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.
The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.
![A+BC\rightarrow AC+B](https://tex.z-dn.net/?f=A%2BBC%5Crightarrow%20AC%2BB)
Metal A is more reactive than metal B.
We are given:
Iron can reduce copper, silver can reduce gold, sodium can reduce iron and copper can reduce silver metal.
The increasing order of reactivity thus follows:
![Au](https://tex.z-dn.net/?f=Au%3CAg%3CCu%3CFe%3CNa)
where, sodium is most reactive and gold is least reactive
For the given options:
<u>Option 1:</u> Copper cannot easily reduce sodium ion to sodium metal because it is less reactive.
![Cu(s)+Na^+(aq.)\rightarrow \text{ No reaction}](https://tex.z-dn.net/?f=Cu%28s%29%2BNa%5E%2B%28aq.%29%5Crightarrow%20%5Ctext%7B%20No%20reaction%7D)
<u>Option 2:</u> Iron cant easily reduce gold ion to gold metal because it is more reactive.
![Fe(s)+3Au^+(aq.)\rightarrow Fe^{3+}(aq.)+3Au(s)](https://tex.z-dn.net/?f=Fe%28s%29%2B3Au%5E%2B%28aq.%29%5Crightarrow%20Fe%5E%7B3%2B%7D%28aq.%29%2B3Au%28s%29)
<u>Option 3:</u> Silver cannot easily reduce iron ion to iron metal because it is less reactive.
![Ag(s)+Fe^{3+}(aq.)\rightarrow \text{ No reaction}](https://tex.z-dn.net/?f=Ag%28s%29%2BFe%5E%7B3%2B%7D%28aq.%29%5Crightarrow%20%5Ctext%7B%20No%20reaction%7D)
Hence, the true statement is iron can reduce
to gold metal
Examination by a test; experiment, as in chemistry, metallurgy, etc.