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xxMikexx [17]
3 years ago
12

What is the temperature used for the extension step?

Physics
1 answer:
lisabon 2012 [21]3 years ago
8 0
<h2>72°C</h2>

Explanation:

  • The polymerase chain response (PCR) could be a strategy to quickly open up groupings of DNA.
  • Amid a normal PCR, format DNA (containing the locale of intrigued) is blended with deoxynucleotides (dNTPs), a DNA polymerase and small segments of DNA called primers.
  • PCR involves a series of temperature cycles.
  • The temperature used for the extension step is 72°C.
  • The temperature that is used during the extension phase is dependent on the DNA polymerase that is used.
  • Amid the expansion step (ordinarily 68°C-72°C) the polymerase amplifies the groundwork to create an early DNA strand. This prepare is rehashed different times
  • Generally at this stage, the reaction mixture is heated to a temperature intermediate between the denaturation and annealing temperatures. The optimal temperature for Taq polymerase is 72°C.
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car rides on four wheels that are connected to the body of the car by spring assemblies that let the wheels move up and down ove
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78.4 KN/m

Explanation:

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3 0
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1. In Newton’s ring experiment, the diameter of the 5th ring is 0.30 cm and diameter of 15th the ring is 0.62 cm. Find the diame
IgorC [24]

Answer:

Diameter of Newton’s 5th ring = 0.30 cm

Diameter of Newton’s 15th ring = 0.62 cm

Diameter of Newton’s 25th ring = ?

From Newton’s rings experiment we infer that

D2n+m − D2n = 4λmR

For the 5th and 15th rings we have

D215 − D25 = 4λ * 10 * R _______ (1) (m = 10)

For 15th and 25th rings

D225 − D215 = 4λ * 10 * R _______ (2) (m = 10)

We equate the two derivatives

Equation (2) = Equation (1)

D225 − D215 = D215 − D25

D225 = 2D215 – D25

Substituting the values into the equation

D225 = 2 * 0.62 * 0.62 – 0.3 * 0.3 =0.6788 cm2

D25 = 0.8239 cm

4 0
3 years ago
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