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xxMikexx [17]
3 years ago
12

What is the temperature used for the extension step?

Physics
1 answer:
lisabon 2012 [21]3 years ago
8 0
<h2>72°C</h2>

Explanation:

  • The polymerase chain response (PCR) could be a strategy to quickly open up groupings of DNA.
  • Amid a normal PCR, format DNA (containing the locale of intrigued) is blended with deoxynucleotides (dNTPs), a DNA polymerase and small segments of DNA called primers.
  • PCR involves a series of temperature cycles.
  • The temperature used for the extension step is 72°C.
  • The temperature that is used during the extension phase is dependent on the DNA polymerase that is used.
  • Amid the expansion step (ordinarily 68°C-72°C) the polymerase amplifies the groundwork to create an early DNA strand. This prepare is rehashed different times
  • Generally at this stage, the reaction mixture is heated to a temperature intermediate between the denaturation and annealing temperatures. The optimal temperature for Taq polymerase is 72°C.
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An alloy that contains mainly copper and tin is bronze

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Select the sentence that best describes why copper and some other metals are good conductors.
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Suppose that in a lightning flash the potential difference between a cloud and the ground is 1.0*109 V and the quantity of charg
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Answer:

a) U_{e} = 3 \times 10^{10}\,J, b) v \approx 7745.967\,\frac{m}{s}

Explanation:

a) The potential energy is:

U_{e} = Q \cdot \Delta V

U_{e} = (30\,C)\cdot (1.0\times 10^{9}\,V)

U_{e} = 3 \times 10^{10}\,J

b) Maximum final speed:

U_{e} = \frac{1}{2}\cdot m \cdot v^{2}\\v = \sqrt{\frac{2\cdot U_{e}}{m} }

The final speed is:

v=\sqrt{\frac{2\cdot (3 \times 10^{10}\,J)}{1000\,kg} }

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3 0
3 years ago
3. The soccer kicker kicks a 2 kg football with a force of 68 N. How fast will the ball accelerate down the field?
Katen [24]

Answer:

\boxed {\boxed {\sf m= 2 \ kg , \\a= 34 \ m/s^2,  \\\F= 68 \ N}}

Explanation:

The formula for force is:

F=m*a

If we rearrange the formula to solve for a (acceleration), the formula becomes

\frac{F}{m} =a

The force is 68 Newtons. Let's convert the units to make the problem easier later on. 1 N is equal to 1 kg*m/s², so the force of 68 N is equal to 68 kg*m/s².

The mass is 2 kilograms.

F=68 \ kg*m/s^2 \\m= 2\ kg

Substitute the values into the formula.

\frac{68 \ kg*m/s^2}{2 \ kg} =a

Divide. Note that the kilograms will cancel each other out (hence why we changed the units).

\frac{68 \ m/s^2}{2}=a

34 \ m/s^2=a

The acceleration is<u> </u><u>34 meters per second squared.</u>

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Answer:

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