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nevsk [136]
3 years ago
8

A block slides down a rough ramp with a 30-degree incline as shown.

Physics
1 answer:
In-s [12.5K]3 years ago
5 0

Answer:

Image 4 ?

Explanation:

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Suppose an astronaut has landed on Planet * Fully equipped, the astronaut has a
gayaneshka [121]

From the calculations, the value of the acceleration due to gravity is 0.38 m/s^2.

<h3>What is weight?</h3>

The weight of an object is obtained as the product of the mass of the body and the acceleration due to gravity.

Thus;

When;

mass = 120 kg

weight =  46 N

acceleration due to gravity = 46 N/120 kg

=0.38 m/s^2

Learn more about acceleration due to gravity :brainly.com/question/13860566

#SPJ1

7 0
2 years ago
If the emf produced in a wire is 0.88 volts and the wire moves perpendicular to a magnetic field of strength 0.075 newtons/amper
Elza [17]
Emf = d (phi-B) / dt 
<span>B dA/dt, where dA/dt is the area swept out by the wire per unit time. </span>
<span>0.88 V = (0.075 N/(A m)) (L)(4.20 m/s), so </span>
<span>L = (0.88 J/C) / [ (0.075 N s/C m)(4.2 m/s) ] = about 3 meters</span>
6 0
3 years ago
Read 2 more answers
How long does it take someone to run 8 miles if they are running at a speed of 7 km/hr?
ZanzabumX [31]

Answer:

1.84 hours or 110.4 minutes

Explanation:

8 miles             1.61 km                 1 hr

------------    x   -----------------  x   -------------- = 1.84 hours or 110.4 minutes

                          1 mile                7  km    

7 0
3 years ago
I have a voltage source of 12V but a light that only burns at 5V. The lamp works on 18 mA. Calculate the resistance that you EXT
ratelena [41]

Answer:

The resistance that will provide this potential drop is 388.89 ohms.

Explanation:

Given;

Voltage source, E = 12 V

Voltage rating of the lamp, V = 5 V

Current through the lamp, I = 18 mA

Extra voltage or potential drop, IR =  E- V  

                                                    IR = 12 V - 5 V = 7 V

The resistance that will provide this potential drop (7 V) is calculated as follows:

IR = V

R = \frac{V}{I} = \frac{7 \ V}{18 \times 10^{-3} A} \ = 388.89 \ ohms

Therefore, the resistance that will provide this potential drop is 388.89 ohms.

7 0
3 years ago
How do you solve <img src="https://tex.z-dn.net/?f=4x%5E%7B3%7D" id="TexFormula1" title="4x^{3}" alt="4x^{3}" align="absmiddle"
Vlad1618 [11]

Hello There!

Here's a explanation!

Let's solve your equation step-by-step.

4x^3=2x^-^1

4x^3=\frac{2}{x}

Step 1: Multiply both sides by x.

4x^4=2

\frac{4x^4}{4} =\frac{2}{4}

(Divide both sides by 4).

x^4=\frac{1}{2}

x=+(\frac{1}{2} )^(^\frac{1}{4} ^)

Take the root.

ANSWER!

x=0.840896 Or x=-0.840896

Hopefully, this helps you!!

AnimeVines

8 0
3 years ago
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