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sergiy2304 [10]
3 years ago
13

What happens to the gravitational potential energy between two particles if the distance between them is halved? (a) It does not

change(b) It is multiplied by 2(c) It is multiplied by 4(d) It is multiplied by 8What happens to the gravitational force between two particles if the distance between them is doubled? (a) It does not change(b) It decreases by a factor of 2(c) It decreases by a factor of 4(d) It decreases by a factor of 8
Physics
1 answer:
mr_godi [17]3 years ago
7 0

Answer:

The gravitational potential energy between two particles, if the distance between them is halved, is multiplied by 4 (option c).

Explanation:

The gravitational force is the force of mutual attraction that two objects with mass experience.

The Law of Universal Gravitation enunciated by Newton says that every material particle attracts any other material particle with a force directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them. Mathematically this is expressed as:

F=G*\frac{m1*m2}{r^{2} }

where m1 and m2 are the masses of the objects, r the distance between them and G a universal constant that receives  the name of constant of gravitation.

If the distance between two particles is reduced by half, then, where F' is the new value of the gravitational force:

F'=G*\frac{m1*m2}{(\frac{r}{2} )^{2} }

F'=G*\frac{m1*m2}{\frac{(r )^{2} }{2^{2} } }

F'=G*\frac{m1*m2}{\frac{(r )^{2} }{4} }

F'=4*G*\frac{m1*m2}{r^{2} }

F'=4*F

<u><em> The gravitational potential energy between two particles, if the distance between them is halved, is multiplied by 4 (option c).</em></u>

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Answer:

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2 years ago
Which forces tend to slow down an object
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8 0
3 years ago
a bird flies 25.0 m in the direction 55° east of south to its nest. the bird then flies 75.0 m in the direction 55° west of nort
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The northward components of the resultant displacement is 40.96 m and the westward components of the resultant displacement of the bird from its nest is 28.68 m.

<h3>Displacement of the bird</h3>

The displacement of the bird is the change in the position of the bird.

<h3>Vertical component of the bird's displacement </h3>

Vy₁ = -25 m  x   sin(55)

Vy₁ = -20.48 m

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Vy₂ = 61.44 m

Total vertical displacement = 61.44 m - 20.48 m = 40.96 m

<h3>Horizontal component of the bird's displacement </h3>

Vx₁ = -25 m  x   cos(55)

Vx₁ = -14.34 m

Vx₂ = 75 m   x    cos(55)

Vx₂ = 43.02 m

Total horizontal displacement = 43.02 m - 14.34 m = 28.68 m

Learn more about displacement here: brainly.com/question/2109763

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A crate remains stationary after it has been placed on a ramp inclined at an angle with the horizontal. Which of the following s
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Answer:

d. It is equal to the component of the gravitational force acting down the ramp.

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Because the Force of Friction that is opposing the motion of the crate along the inclination side.

Therefore this Frictional force is balanced or equal to the force that is driving the inclined force.

Hence Frictional Force is equal to the Gravitational Force that is acting in the ramp, that is why the crate is stationery.

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