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oee [108]
3 years ago
7

For the equation BaCI2 + Na2SO4 > BaSO4 + 2NaCI

Physics
1 answer:
Umnica [9.8K]3 years ago
8 0
B I think aooooooo oops
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Kelly's mother is taking her temperature to see if she has a fever. Which unit of measurement could be used to measure Kelly's b
Sergeeva-Olga [200]

Answer:

The answer is A.

Explanation:

To measure a temperature, you have degrees with Farenheight or Celsius. Meters are measured with a meter stick while grams and kilograms are measurments for weight.

Therefore, degrees Celsius is your answer.

Best of Luck to you!

7 0
3 years ago
Read 2 more answers
A 7.5 kg block is placed on a table. if it's bottom surface area is 0.6m2, how much pressure does the block exert on the tableto
xeze [42]
The answer to this is B.
3 0
3 years ago
After a check up, a person now has a far point of 100 cm, but with good near point vision. He needs to wear a new pair of correc
lakkis [162]

Answer:

so his far point according to this pair of glass is 200 cm

Explanation:

power of old pair of corrective glasses is given as

P = -0.5 dioptre

now we have

f = \frac{1}{P}

f = -2 m

f = -200 cm

now we know that for normal vision the maximum distance of vision is for infinite distance

so by lens formula we have

\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}

\frac{1}{d_i} + 0 = \frac{1}{200}

d_i = 200 cm

so his far point according to this pair of glass is 200 cm

7 0
3 years ago
Why is the unit of momentum called derived unit​
Mnenie [13.5K]

Answer:

the SI unit of momentum is :- kg.ms-1

and we know that,

kinetic energy = 1/2 mv2

E=p2/2m

p=(2Em)1/2

so the derived units are (J.kg)1/2

Explanation:

8 0
3 years ago
A heat engine running backward is called a refrigerator if its purpose is to extract heat from a cold reservoir. The same engine
Goryan [66]

Answer:

a) 2.85 kW

b) $ 432

c) $ 76.95

Explanation:

Average price of electricity = 1 $/40 MJ

Q = 20 kW

Heat energy production = 20.0 KJ/s

Coefficient of performance,  K = 7

also

K=(QH)/Win

Now,

Coefficient of Performance, K = (QH)/Win = (QH)/P(in) = 20/P(in) = 7

where

P(in) is the input power

Thus,

P(in) = 20/7 = 2.85 kW

b) Cost = Energy consumed × charges

Cost = ($1/40000kWh) × (16kW × 300 × 3600s)

cost = $ 432

c) cost = (1$/40000kWh) × (2.85 kW × 200 × 3600s) = $76.95

4 0
3 years ago
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