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harina [27]
4 years ago
13

I need help

Mathematics
2 answers:
NeTakaya4 years ago
7 0
The answer is 15 because 15>11.3
Charra [1.4K]4 years ago
5 0
OK so if you have, oh I don't know, 11.3 loaves of bread, would you have more if you had 15, owed someone 14, had 4, or had 9? 
The correct answer is B because it is the only one that is larger than 11.3
You might be interested in
The rate of change in sales for Garmin from 2008 through 2013 can be modeled by
Zina [86]

Answer:

a) The model for the sales of Garmin is represented by S(t) = -\frac{81}{2500}\cdot t^{3} + \frac{267}{250}\cdot t^{2} - 11.9\cdot t + 47.112.

b) The average sales of Garmin from 2008 through 2013 were $ 2.5 billion.

Step-by-step explanation:

a) The model for the sales of Garmin is obtained by integration:

S(t) = -0.0972\int {t^{2}} \, dt + 2.136\int {t}\,dt -11.9 \int\,dt

S(t) = -\frac{81}{2500}\cdot t^{3} + \frac{267}{250}\cdot t^{2} - 11.9\cdot t + C (1)

Where C is the integration constant.

If we know that t = 9 and S(t) = 2.9, then the model for the sales of Garmin is:

-\frac{81}{2500} \cdot 9^{3} + \frac{267}{250}\cdot 9^{2}-11.9\cdot (9) + C = 2.9

C = 47.112

The model for the sales of Garmin is represented by S(t) = -\frac{81}{2500}\cdot t^{3} + \frac{267}{250}\cdot t^{2} - 11.9\cdot t + 47.112.

b) The average sales of the Garmin from 2008 through 2013 (\bar{S}) is determined by the integral form of the definition of average, this is:

\bar{S} = \frac{1}{13 - 8} \cdot \int\limits^{13}_{8} {S(t)} \, dt (2)

\bar S = \frac{1}{5}\cdot \int\limits^{13}_{8} {\left[-\frac{81}{2500}\cdot t^{3} + \frac{267}{250}\cdot t^{2}-11.9\cdot t + 47.112  \right]} \, dt

\bar S = \frac{1}{5}\cdot \left[-\frac{81}{10000}\cdot (13^{4}-8^{4}) +\frac{89}{250}\cdot (13^{3}-8^{3}) -\frac{119}{20}\cdot (13^{2}-8^{2}) +47.112\cdot (13-8)   \right]\bar{S} = \frac{1}{5}\cdot (-198.167+599.86-624.75+235.56)

\bar{S} = 2.5

The average sales of Garmin from 2008 through 2013 were $ 2.5 billion.

7 0
3 years ago
HELLPPPP ANSWERRR AND EXPLAIN!!!!!​
bixtya [17]

Answer:

No

Step-by-step explanation:

This is because K and B don't share the same angle measurement. They both will be different numbers that must equal 180 degrees. With that K will be corresponding with J while B will be corresponding with D.

Hope this Helped

5 0
3 years ago
Read 2 more answers
What is the <img src="https://tex.z-dn.net/?f=%5Csqrt%7B10%7D" id="TexFormula1" title="\sqrt{10}" alt="\sqrt{10}" align="absmidd
morpeh [17]
6.32455532 is what my calculator says.
4 0
3 years ago
Area of a rectangle is 36 what is x if the width is x and length is x+5
Reika [66]
If the length is x+5, the width would be x(x+5)=36
5 0
3 years ago
If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by
Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by y = 70t-16t^2.

To find : The average velocity for the time period beginning when t = 2 and lasting.  a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :    

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}

(\text{Average velocity})_{0.1\ s}=696\ ft/s

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}

(\text{Average velocity})_{0.01\ s}=7536\ ft/s

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}  

(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}

(\text{Average velocity})_{0.001\ s}=75936\ ft/s

5 0
4 years ago
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