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harina [27]
4 years ago
13

I need help

Mathematics
2 answers:
NeTakaya4 years ago
7 0
The answer is 15 because 15>11.3
Charra [1.4K]4 years ago
5 0
OK so if you have, oh I don't know, 11.3 loaves of bread, would you have more if you had 15, owed someone 14, had 4, or had 9? 
The correct answer is B because it is the only one that is larger than 11.3
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For every 5 minutes jogged there's 1 lap ran
Stella [2.4K]

Answer:

????? Please explain more

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
What is the exact value of cos(7pi/8)
Damm [24]

Answer:

cos (\frac{7\pi}{8}) = -\frac{\sqrt{2+\sqrt{2}}}{2}

Decimal value: −0.9238795325...

Step-by-step explanation:

Write,

cos \frac{7\pi}{8} = cos (\pi-\frac{\pi}{8}) = −cos \frac{\pi }{8}

Now using half angle formula, cos(x) = 2 cos²(\frac{\pi }{2}) − 1, we can write cos \frac{\pi }{4} = 2

cos²(\frac{\pi }{8}) − 1

This means \frac{1}{\sqrt{2}} + 1 = 2 cos²(\frac{\pi }{8})

2 cos²(\frac{\pi }{8}) = \frac{\sqrt{2}+1}{\sqrt{2}}

cos²(\frac{\pi }{8}) = \frac{\sqrt{2}+1}{2\sqrt{2}}

cos(\frac{\pi }{8}) = \sqrt{\frac{\sqrt{2}+1}{2\sqrt{2}}}

Simplify,

\sqrt{\frac{\sqrt{2}+1}{2\sqrt{2}}} = \sqrt{\frac{2+\sqrt{2}}{4} = \frac{\sqrt{2+\sqrt{2}}}{2}

Hence,

cos (\frac{7\pi}{8}) = −cos (\frac{\pi }{8}) = -\frac{\sqrt{2+\sqrt{2}}}{2}

3 0
3 years ago
Read 2 more answers
Someone please help!
damaskus [11]

Answer:

  1. Red: -2
  2. Blue: 5
  3. Yellow: -4
  4. Green: 3
  5. Orange: -1

5 0
3 years ago
Read 2 more answers
Frankie solved the math problem below. Find the error in Frankie's work and explain it in words, using math language. 2 1/3 - 1
HACTEHA [7]

Given:

The expression is

2\dfrac{1}{3}-1\dfrac{2}{5}

To find:

The error in Frankie's work.

Solution:

We need to simplify 2\dfrac{1}{3}-1\dfrac{2}{5}, so

2\dfrac{1}{3}=2\dfrac{1}{3}\times \dfrac{5}{5}

2\dfrac{1}{3}=2\dfrac{5}{15}

and,

1\dfrac{2}{5}=-1\dfrac{2}{5}\times \dfrac{3}{3}

1\dfrac{2}{5}=-1\dfrac{6}{15}

Now,

2\dfrac{1}{3}-1\dfrac{2}{5}=2\dfrac{5}{15}-1\dfrac{6}{15}

2\dfrac{1}{3}-1\dfrac{2}{5}=(2+\dfrac{5}{15})-(1+\dfrac{6}{15})

2\dfrac{1}{3}-1\dfrac{2}{5}=2+\dfrac{5}{15}-1-\dfrac{6}{15}

2\dfrac{1}{3}-1\dfrac{2}{5}=1-\dfrac{1}{15}

2\dfrac{1}{3}-1\dfrac{2}{5}=\dfrac{14}{15}

Therefore, there is error in Frankie's last step. In that step, he did not subtract the mixed fraction correctly.

8 0
3 years ago
Solve for g.<br> 1<br> f= 1/8<br> (g+h-k)
Taya2010 [7]
G = 3f-h+k

hope this helps :)
8 0
3 years ago
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