All categories

3 years ago

What type of air masses might make up the cold air mass in a cold front

Chemistry

2 answers:

Elena L [17]3 years ago

4 0

Answer:

continental polar air masses

Explanation:

forms over Canada, move down from North Pole, bring bitterly cold and dry air to the northern United States during the winter.

salantis [7]3 years ago

3 0

The air mass in a cold front is air masses that make up cold

You might be interested in

What fraction of 2 years is 10 months

zzz [600]

Answer:

10/24

Simplified: 5/12

Explanation:

Well first, let's convert years into months

1 year = 12 months which means 2 years = 24 months

In fraction form we would write this as 10/24

If the question asks for it to be simplified, then simply

Both 10 and 24 evenly fit 2

Therefore, divide both the numerator and the denominator by 2

10 ÷ 2 / 24 ÷ 2

5/12

This can no longer be simplified

8 0

3 years ago

Does sugar can dissolve in ccl4

wel

Answer:

Sugar is a polar compound , in the solid state of it Hydrogen bond strongly binds the molicules of sugar together. Being a non polar solvent and low polarity difference between Cl and C atom C—Cl bond in CCl4 is unable to form hydrogen bond. That's why sugar can't be soluble in CCl4.

Explanation:

8 0

3 years ago

Explain why it is important to assume that the rate of radioactive decay aka radioactivity will remain constant over time?

marusya05 [52]

Answer and Explanation:

It's very important to assume that the rate of radioactive decay will remain constant over time to make scientists' lives easier when calculating the ages of fossils, compounds, etc.

If the rate changes, it would be extremely challenging for people to figure out the relative ages of rock strata, fossils, or other substances with radioactive elements in them. This is a fundamental assumption in order to be able to use radioactive dating.

Hope this helps!

8 0

4 years ago

Read 2 more answers

Write a balanced half-reaction for the reduction of bismuth oxide ion to bismuth ion in basic aqueous solution. Be sure to add p

Butoxors [25]

Answer:

$3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$

Explanation:

Hello there!

In this case, according to the required half-reaction, we start by setting it up from bismuth (V) oxide ion to bismuth (III) ion:

$BiO_3^-\rightarrow Bi^{3+}$

Thus, next realize that the oxidation state of Bi in BiO3^- is 5+ because oxygen is 2- (-2*3+x=-1;x=-1+6;x=+5), so we obtain:

$(Bi^{5+}O_3)^-\rightarrow Bi^{3+}$

Thereafter, we realize three water molecules are needed on the right in order to balance the oxygens and consequently 6 hydrogen atoms on the left to balance hydrogen:

$6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O$

Now, since the balance is is basic media, we add six molecules of hydroxide ions in order to produce water with the hydrogen ones:

$6OH^-+6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O-3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$

Then, we accommodate the waters to obtain:

$3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$

Best regards!

7 0

3 years ago

Convert 281 K to degrees Celsius. 281 K = _____ -8°C 554°C 8°C

Lisa [10]

Answer:

8°C

Explanation:

3 0

3 years ago