It moves the graph 5 steps downwards on the y axis.
Since you don't want any leftover items, you have to find the greatest common factor (GCF) of both the crayons and bubbles. Since the highest common factor for both 28 and 12 is 4, the greatest number of gift bags you can make without any leftover items would be 4 gift bags.
Hope I could help.
Rise over run
13-5=8 rise
6-2=4 run
The answer is c
Answer:
3a^2b-5ab^2
Step-by-step explanation:
Answer:
12
bcz he can't put a 0.725 fish so it will be rounded up back to 12
