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Marina86 [1]
3 years ago
12

How many times can 4 go into 68

Mathematics
2 answers:
katrin2010 [14]3 years ago
7 0
4 can go into 68, 17 times. Hope this helps 68/4 = 17
stira [4]3 years ago
6 0
4 can go into 68, 17 times. So to solve it, it would be 68/4 = 17
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Find the measurement of the segment. QT = 28.5 in., QV = 64.7 in.
statuscvo [17]
The question requires getting the length of TV

<u><em>Answer:</em></u>
TV = 36.2 in

<u><em>Explanation:</em></u>
We are given that point T lies on line QV. The scenario is shown in the attached image.
<u>This means that:</u>
QV = QT + TV

<u>We have:</u>
QT = 28.5 in
QV = 64.7 in

<u>Substitute with the values to get the length of TV as follows:</u>
QV = QT + TV
64.7 = 28.5 + TV
TV = 64.7 - 28.5
TV = 36.2 in

Hope this helps :)

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3 years ago
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Step-by-step explanation:

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3 years ago
What number has factors of 2 and 3 and multiples of 12 and 18?
patriot [66]
4 and 6. Hope this helps
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3 years ago
8.The weight distribution of parcels sent in a certain manner is normal with mean value 12lb and standard deviation 3.5 lb. The
Sladkaya [172]

Answer:

The value is c = 21.1445.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The weight distribution of parcels sent in a certain manner is normal with mean value 12lb and standard deviation 3.5 lb.

This means that \mu = 12, \sigma = 3.5

What value of c is such that 99% of all parcels are at least 1 lb under the surcharge weight?

This 1 added to the value of X for the 99th percentile, which is X when Z has a p-value of 0.99, so X when Z = 2.327.

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1 + 20.1445 = 21.1445

The value is c = 21.1445.

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3 years ago
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