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vodomira [7]
2 years ago
6

In the figure, a baseball is hit at a height h = 1.20 m and then caught at the same height. It travels alongside a wall, moving

up past the top of the wall 1.1 s after it is hit and then down past the top of the wall 4.8 s later, at distance D = 54 m farther along the wall. (a) What horizontal distance is traveled by the ball from hit to catch? What are the (b) magnitude and (c) angle (relative to the horizontal) of the ball's velocity just after being hit? (d) How high is the wall?
Physics
1 answer:
pickupchik [31]2 years ago
8 0

Answer:

D.

Explanation:

The ball travels distance D in ∆t = 2.60 s. Therefore, the x component of the initial velocity is D =v

ox

​

 ⇒ ∆t = D/∆t = 15.4 m/s Due to the symmetry of projectile motions, it takes 1.2 seconds the ball to reach the initial height after passing the top of the wall downward. Therefore, the total flight time is t

tot

​

 = 1.2 + 2.6 +1.2 = 5 s The horizontal range is R = v

ox

​

t

tot

​

 = 77.0 m  

By symmetry, the ball reaches the peak of the motion at time t

top

​

 = t

tot

​

/2 = 2.5 s At the peak, the y component of the velocity is zero. Thus we have 0 = v

oy

​

 – gt

top

​

 ⇒ v

oy

​

  = gt

top

​

= 24.5 m/s The height of the wall is equal to the height of the ball at t = 1.2 s h = y (t = 1.2 s) = v

oy

​

 +v

oy

​

t – (1/2)gt

2

  = 23.3 m

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Sergio039 [100]

Answer:

r=61.65m

Explanation:

Since the package remains in contact with the car's seat, the package's speed is equal to the car's speed. At the top on the mountain the package's centripetal force must be equal to its weight:

mg=F_c

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Here v is the linear speed of the object and r is the radius of curvature. We need to convert the linear speed to \frac{m}{s}:

88.5\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}=24.58\frac{m}{s}

Now, we calculate r:

mg=\frac{mv^2}{r}\\r=\frac{v^2}{g}\\r=\frac{(24.58\frac{m}{s})^2}{9.8\frac{m}{s^2}}\\\\r=61.65m

3 0
3 years ago
Resonance structures have _______ connectivity of atoms and _______ distribution of electrons.
Arte-miy333 [17]

Answer:

Resonance structures have <u> </u><u>same</u><u>  </u>  connectivity of atoms and <u> differ only in</u> distribution of electrons.

Explanation:

Atoms supply the electrons from their outer electron shells. Electrons are found free in nature and are grouped around the nucleus into shells. Electrons can be further explained as negatively charged subatomic particle. Electrons have properties of both particles and waves and they can be moved around.

Resonance structures are imaginary structures and not all of them are created equally. Resonance structures have two or more possible electron structures, and, the resonance structures for a particular substance sometimes have different energy and stability. When resonance structures are identical, they are important descriptions  of the molecule. The position of the atoms is the same in the various resonance structures of a compound, but the electrons are distributed differently around the structure.

3 0
4 years ago
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Out of the given options, weight is influenced by mass and gravity

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<u>Explanation: </u>

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The mass is always same irrespective the location but the weight may vary from one place to the other while talking for the bigger picture. For example, the object's weight may be 60 kg on Earth but when it is measured on the moon, it will be lesser.

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6 0
3 years ago
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7 0
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ozzi

Answer:

e. 400 Hz

Explanation:

In closed organ pipe,  only odd harmonics of fundamental note is possible .

The fundamental frequency is 200 Hz . Then other overtones will be having following frequencies .

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Frequency not possible is 400 Hz .

7 0
4 years ago
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