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3 years ago

13

Can anyone please help me with this question!!

2 answers:

mamaluj [8]3 years ago

8 0

Answer:

its is A,B and D

Step-by-step explanation:

find the square root of both and find the values that lie between them :)

4vir4ik [10]3 years ago

4 0

It’s a, b , d Hope this helps

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vfiekz [6]

Answer:

11/12 = 3/4

Step-by-step explanation:

sorry that's the only one I know :(

5 0

3 years ago

Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

vodka [1.7K]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

7 0

2 years ago

PLEASE ANSWER FAST AS POSSIBLE I HAVE 40 LESSONS DUE BY 12 PM :(

Sophie [7]

Try B, hope that helps :)

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3 years ago

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6.Angle 30degrees + x is equal to 180 degrees. Find x

Harrizon [31]

The answer is 150 because 30+150=180

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3 years ago

Jerry has been staying up late at night to get in some extra study time. He hopes to get accepted into his favorite college and

svet-max [94.6K]

(Answer coming from someone who’s stressed himself)
Upset stomach.
When you’re stressed, you have a higher heart rate, difficulty sleeping, and feeling exhausted the whole day.

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3 years ago

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