3 years ago

What will be the acceleration of an 8 kg object when something hits it with an 12 N force?

1 answer:

3 0

$\sf Force = mass \times acceleration\\\\12~N = 8~kg \times acceleration\\\\ acceleration = \frac{12~N}{8~kg} \\\\\boxed {\sf a = 1.5~ \frac{m}{s^2} }$

You might be interested in

Which feature in this graph represents:

Rom4ik [11]

Answer:

almost 100% positive its B but dont take me up on it

3 0

3 years ago

Tall towers support power lines h = 59 m above the ground and 19 m apart that run from a hydroelectric plant to a large city, ca

Nookie1986 [14]

Answer:

a) 4.25 x 10∧-5 T

b) 16.03 mv

Explanation:

the solution is shown in the pictures attached

8 0

3 years ago

Find the value of T1 if 1 = 30°, 2 = 60°, and the weight of the object is 139.3 newtons.

Lelechka [254]

Answer:

Option A (69.56 newtons) is the appropriate solution.

Explanation:

According to the question,

On the X-axis,

⇒ $T_1Cos30^{\circ}-T_2Cos60^{\circ}=0$

or,

$T_1Cos 30^{\circ}=T_2Cos60^{\circ}$

On substituting the values, we get

$T_1\times \frac{\sqrt{3} }{2}=T_2\times \frac{1}{2}$

$T_1\times \sqrt{3} =T_2$ ....(equation 1)

On the Y-axis,

⇒ $T_1Sin30^{\circ}+T_2Sin60^{\circ}=139.3 \ N$

$\frac{T_1}{2} +\frac{\sqrt{3} }{2} =139.2 \ N$

$T_1+\sqrt{3}T_2=139.2\times 2$

From equation 1, we get

$T_1+\sqrt{3}\times \sqrt{3}T_1 =278.4 \ N$

$T_1+3T_1=278.4 \ N$

$4T_1=278.4 \ N$

$T_1=\frac{278.4}{4}$

$=69.6 \ N$

6 0

3 years ago

Which of the following types of energy transfers can take place when matter is not present?

never [62]

Answer:

heat

Explanation:

5 0

4 years ago

The space shuttle edeavor is launched to altitude of 500,000 m above the surface of earth. The shuttle travels at an average rat

NikAS [45]

Answer:

714s

Explanation:

t=H/v=500000m/700m/s=714s

7 0

3 years ago