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3 years ago

Which of these statements best supports the conclusion that a substance is in the plasma phase?

Physics

1 answer:

emmasim [6.3K]3 years ago

3 0

The colorless watery fluid of the blood and lymph that containing

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The early earth was much cooler than it is today. <br><br> a. True <br><br> b. False

Pie

This statement is true. Early earth was much cooler than it is today.

This is because the pollution as well as the population number was very small compared to nowadays population and pollution.
The pollution mainly is causing a decay in the ozone layer which protects the earth from uv rays. Thus, more of these rays enter the atmosphere and increase the temperature.
The increase in population along with the decrease in green areas leads to the increase in the percentage of carbon dioxide in the atmosphere, which again leads to an increase in the temperature.

5 0

3 years ago

A scuba diver, submerged under water looks up and seessunlight

maw [93]

Answer:

$41.7975\ ^{\circ}$

Explanation:

$n_2$ = Refraction index of water = 1.333

$n_1$ = Refraction index of air = 1

$\theta_2$ = Angle of sunlight = 30°

From Snell's law we have

$\dfrac{n_1}{n_2}=\dfrac{sin\theta_2}{sin\theta_1}\\\Rightarrow \theta_1=sin^{-1}\dfrac{n_2sin\theta_2}{n_1}\\\Rightarrow \theta_1=sin^{-1}\dfrac{1.333sin30}{1}\\\Rightarrow \theta_1=41.7975\ ^{\circ}$

The angle measured from the vertical does the sunlight strike thesurface of the water is $41.7975\ ^{\circ}$

5 0

3 years ago

When is your kinetic energy the least when swinging on a park swing?

Afina-wow [57]

Answer:

An active pendulum has the most kinetic energy at the lowest point of its swing when the weight is moving fastest.

Explanation:

SO YOU HAVE THE LEAST KINETIC ENERGY AT THE HIGHEST POINT OF THE SWING WHEN IT'S NOT ACTIVE

7 0

3 years ago

A solenoid having an inductance of 6.95 μh is connected in series with a 1.24 kω resistor. (a) if a 12.0 v battery is connected

Serggg [28]

In electrical circuit, this arrangement is called a R-L series circuit. It is a circuit containing elements of an inductor (L) and a resistor (R). Inductance is expressed in units of Henry while resistance is expressed in units of ohms. The relationship between these values is called the impedance, denoted as Z. Its equation is

Z = √(R^2 + L^2)
Z = √((1.24×10^3 ohms)^2 + (6.95×10^-6 H)^2)
Z = 1,240 ohms

The unit for impedance is also ohms. Since the circuit is in series, the voltage across the inductor and the resistor are additive which is equal to 12 V. Knowing the impedance and the voltage, we can determine the maximum current.
I = V/Z=12/1,240 = 9.68 mA
But since we only want to reach 73.6% of its value, I = 9.68*0.736 = 7.12 mA. Then, the equation for R-L circuits is
$I= \frac{V( 1- e^{-t/τ} )}{R}$ , where τ = L/R = 6.95×10^-6/1.24×10^3 = 5.6 x 10^-9
Then,
$7.12x 10^{-3} = \frac{12( 1- e^{-t/5.6x 10^{-9} } )}{1240}$

t = 7.45 nanoseconds
Part B.) If t = 1.00τ, then t/τ = 1. Therefore,
$I= \frac{12( 1- e^{-1 } )}{1240}$

I = 6.12 mA

3 0

3 years ago

What is 0.94kg divided by 2.4n

LuckyWell [14K]

Answer:

0.39166666666

Explanation:

7 0

3 years ago