Derive derive an expression for time period of simple pendulum t = 2π√1÷g by using dimensional method
1 answer:
You might be interested in
Answer:
v(t) = 27 units
Explanation:
The function s(t) represents the position of an object at time t moving along a line such that,
and
We need to find the average velocity of the object over the interval of time [2,6]. The velocity of the object is equal to the total distance divided by time. It is given by :
v(t) = 27 units
So, the average velocity of the object is 27 units. Hence, this is the required solution.
Answer:
-0.4 m/s
-3.552 m/s
Explanation:
= Mass of first glider = 0.5 kg
= Mass of second glider = 0.3 kg
= Initial Velocity of first glider = 2 m/s
= Initial Velocity of second glider = -2 m/s
= Final Velocity of first glider
= Final Velocity of second glider = 2 m/s
As the linear momentum of the system is conserved we have
The velocity of glider A is -0.4 m/s
= 0
= -5 m/s
= 0.92 m/s
The velocity of glider A is -3.552 m/s