Answer: c) increases
Explanation:
Pressure increases with decreasing height
Closer to the sun . . . orbital speed is faster.
Farther from the sun . . . orbital speed is slower.
Flag answer: Answer 13 Answer 13
Answer:
38 cm from q1(right)
Explanation:
Given, q1 = 3q2 , r = 60cm = 0.6 m
Let that point be situated at a distance of 'x' m from q1.
Electric field must be same from both sides to be in equilibrium(where EF is 0).
=> k q1/x² = k q2/(0.6 - x)²
=> q1(0.6 - x)² = q2(x)²
=> 3q2(0.6 - x)² = q2(x)²
=> 3(0.6 - x)² = x²
=> √3(0.6 - x) = ± x
=> 0.6√3 = x(1 + √3)
=> 1.03/2.73 = x
≈ 0.38 m = 38 cm = x
I disagree with that opinion, and I have solid Physics to back me up.
The forces of gravity are always equal in both directions. The sun pulls the Earth with exactly the same force with which the Earth pulls the sun.
It may seem weird, but your weight on Earth is exactly the same as the Earth's weight on you. For the same reason.
