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Butoxors [25]
2 years ago
6

This distance from the Earth to the Sun given above is a standard for measuring other distances in the solar system and is calle

d an Astronomical Unit or AU. 1AU=_________miles. Write this as a ratio:_________
Physics
1 answer:
sineoko [7]2 years ago
5 0

Answer:

The Astronomical Unit (AU) is approximately 92.96\times 10^{6}\,mi, the ratio of Astronomical Units per mile is r = 1\,AU\,:\,92.96\times 10^{6}\,mi.

Explanation:

The distance from the Earth to the Sun is approximately 92.96\times 10^{6}\,mi, then the Astronomical Unit (AU) is approximately 92.96\times 10^{6}\,mi. The ratio can be described by the quantity of miles per Astronomical Unit, then we define:

r = 1\,AU\,:\,92.96\times 10^{6}\,mi.

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If we increase the speed of rotation of wheel then the sound produced by cardboard touching the spokes of the wheel will become
Anarel [89]

it will become shrill

5 0
3 years ago
Why are we not crushed by the weight of the atmosphere on our shoulders?
antiseptic1488 [7]

Answer:

Due to equal pressure in all the direction at a particular level in a fluid medium (Pascal's Law)

Explanation:

We are not crushed by the weight of the atmosphere because atmosphere is a fluid and we are immersed into it. So, according to the Pascal's law the the pressure a each point in a horizontal level is equal in all the direction irrespective of the orientation of a body.

Variation of pressure in term of the height of a fluid medium is given as:

P=\rho.g.h

\rho=density of fluid

g = acceleration due to gravity

h = height of the free surface of the fluid from the immersed object.

  • And atmosphere has very less variation of pressure with change in height as it is a rare medium fluid and so for a human height there is very negligible variation of pressure at the heat of a human with respect to his toe.

5 0
3 years ago
What happens to an object when you halve the mass? Hurry please !
Vika [28.1K]

Answer:

It means that if force is constant, as mass is increased, acceleration decreases

Explanation:

5 0
3 years ago
Modeled after the two satellites problem (slide 12 in Lecture13, Universal gravity), imagine now if the period of the satellite
ikadub [295]

Answer:

  R = 6.3456 10⁴  mile

Explanation:

For this exercise we will use Newton's second law where force is gravitational force

      F = m a

The satellite is in a circular orbit therefore the acceleration is centripetal

      a = v² / r

Where the distance is taken from the center of the Earth

     G m M / r² = m v² / r

     G M / r = v²

The speed module is constant, let's use the uniform motion relationships, with the length of the circle is

     d = 2π  r

     v = d / t

The time for a full turn is called period (T)

Let's replace

     G M / r = (2π r / T)²

     r³ = G M T²²2 / 4π²

     r = ∛ (G M T² / 4π²)

We have the magnitudes in several types of units

      T = 88.59 h (3600 s / 1h) = 3.189 10⁵ s

      Re = 6.37 10⁶ m

Let's calculate

     r = ∛ (6.67 10⁻¹¹ 5.98 10²⁴ (3,189 10⁵)²/4π²)

     r = ∛ (1.027487 10²⁴)

     r = 1.0847 10⁸ m

This is the distance from the center of the Earth, the distance you want the surface is

     R = r - Re

     R = 108.47 10⁶ - 6.37 10⁶

     R = 102.1 10⁶ m

Let's reduce to miles

      R = 102.1 10⁶ m (1 mile / 1609 m)

     

      R = 6.3456 10⁴  mile

6 0
2 years ago
How much work, in Joules, is required to stop a 1,168 kg car moving with a speed of 24 km/hr?
ANEK [815]
24km/hour=(20/3)m/s
Hence, W=1/2*1168kg*[(20/3)/m/s]^2=25955.56J

6 0
2 years ago
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