Answer:
y=5x + 21
Step-by-step explanation:
y=5x×b
6= -15+b
b=21
Answer:




Step-by-step explanation:
Given
See attachment for proper format of table
--- Sample
A = Supplier 1
B = Conforms to specification
Solving (a): P(A)
Here, we only consider data in sample 1 row.
In this row:
and 
So, we have:



P(A) is then calculated as:


Solving (b): P(B)
Here, we only consider data in the Yes column.
In this column:
and 
So, we have:



P(B) is then calculated as:


Solving (c): P(A n B)
Here, we only consider the similar cell in the yes column and sample 1 row.
This cell is: [Supplier 1][Yes]
And it is represented with; n(A n B)
So, we have:

The probability is then calculated as:


Solving (d): P(A u B)
This is calculated as:

This gives:

Take LCM


Step-by-step explanation:
-w - 11 < or = w - 5
-2w - 11 < or = -5
-2w < or = -16
w > or = -8
Answer:
C: A line travelling to the right with an open dot on p = -3.
Step-by-step explanation:
You use a closed dot when the equation is greater/less than or equal to: 
It goes right because if it went left it would be p < -3.