Answer:
Explanation:
Hello!
In this case, since the combustion of the hamburger released 335.4 kcal of energy and that energy is received by the calorimeter, we can write:
And the heat of the calorimeter is written in terms of the temperature change and the calorimeter constant:
Thus, given the released heat by the hamburger due to its combustion and the temperature change, Cv for the calorimeter turns out:
Best regards!
Answer:
106 mL
Explanation:
In order to be able to answer this question, you must understand what the density of a substance tells you.
The density of a substance is nothing more than the mass of that substance that occupies one unit of volume.
In your case, the density of ethanol is given in Grams per milliliter, which means that one unit of volume will be
1 mL
.
So, ethanol has a density of
0.785 g mL
−
1
, which is equivalent to saying that if you take exactly
1 mL
of ethanol and weigh it, you will end up with a mass of
0.785 g
.
Now, you know that the volume you're using has a mass of
83.3 g
. Well, if you get
0.785 g
for every
1 mL
of ethanol, it follows that this much mass will correspond to a volume of
83.3
g ethanol
⋅
ethanol's density
1 mL
0.785
g ethanol
=
106.11 mL
Rounded to three sig figs, the answer will be
V
ethanol
=
106 mL
Hope this helps
Answer:
8.5 moles of Al₂O₃ will formed
Explanation:
Given data:
Number of moles of Al = 17 mol
Number of moles of Al₂O₃ formed = ?
Solution:
Chemical equation:
4Al + 3O₂ → 2Al₂O₃
Now we will compare the moles of Al₂O₃ with Al.
Al : Al₂O₃
4 : 2
17 : 2/4×17 = 8.5 mol
8.5 moles of Al₂O₃ will formed.
