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Free_Kalibri [48]
2 years ago
7

To produce 40.0 g of silver chromate, you will need at least 23.4 g of potassium chromate in solution as a reactant. All you hav

e on hand in the stock room is 5 L of a 6.00 M K2CrO4 solution. What volume of the solution is needed to give you the 23.4 g K2CrO4 needed for the reaction?
Chemistry
1 answer:
Nata [24]2 years ago
6 0

Answer:

volume of K_2CrO_4 required=20.1 ml

Explanation:

First calculate the number of mole of K_2CrO_4,

given mass of K_2CrO_4=23.4 gram ⇒this is the required mass to produce 40 gram silver chromate

molecular weight=194g/mol

mole=\frac{given \, mass}{molecular\, weight}

mole=0.121 mol

molarity is given and we have also calculated the mole so we will use the relation between molarity,volume and mole i.e.

molarity= \frac{mole}{volume\, in\, L}

6= \frac{0.121}{volume\, in\, L}

volume in L=0.0201 lire

volume of K_2CrO_4 required=20.1 ml

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A rectangular prism of volume 84 cm 3 has a mass of 760 g. What is the density of the rectangular prism? 5.8 g•cm 3 9.0 g/cm 3 6
Fiesta28 [93]

Answer:

9.0 g/cm³

Explanation:

Density can be computed with the formula:

D=\dfrac{M}{V}

Where:

D = Density

M = Mass

V = Volume

In your problem we are given:

84 cm³ = volume

760 g = mass

So we just plug in our given into the formula:

D=\dfrac{M}{V}

D=\dfrac{760g}{84cm^{3}}

D=9.05g/cm^{3}

The answer would then be:

9.0 g/cm³

3 0
3 years ago
3.
Alecsey [184]

Answer:

<h3>no it is not allowed</h3>

Explanation:

<h3>Liwis structure shows the elements symbol with dots thet represents valance electrons ; in second row elements their atomic number is 3 up to 10 , from Li up to Ne from their electron configuration their valance electron will be from 1 up to 8 respectivelly ,if lewis structure represents the element with it is symbol and dots that represents valance electron the second row elements cannot have more than an octet of valance electrons surrounding it.</h3>

<h3>I think it is help ful for you </h3>
3 0
2 years ago
what is molarity of a sodium hydroxide solution made by combining 2.0 L of 0.60 M NaOH with 495 mL of 3.0 M NaOH? Assume the vol
hammer [34]

Answer:

Molarity of the sodium hydroxide solution is 1.443 M/L

Explanation:

Given;

0.60 M concentration of NaOH contains 2.0 L

3.0 M concentration of NaOH contains 495 mL

Molarity is given as concentration of the solute per liters of the solvent.

If the volumes of the two solutions are additive, then;

the total volume of NaOH = 2 L + 0.495 L = 2.495 L

the total concentration of NaOH = 0.6 M + 3.0 M = 3.6 M

Molarity of NaOH solution = 3.6 / 2.495

Molarity of NaOH solution = 1.443 M/L

Therefore, molarity of the sodium hydroxide solution is 1.443 M/L

8 0
2 years ago
Differentiate the claims made by science from those based on bias.
Readme [11.4K]

Answer:

Scientists seek to eliminate all forms of bias from their research. However, all scientists also make assumptions of a non-empirical nature about topics such as causality, determinism and reductionism when conducting research. Here, we argue that since these 'philosophical biases' cannot be avoided, they need to be debated critically by scientists and philosophers of science.

Explanation:

Scientists are keen to avoid bias of any kind because they threaten scientific ideals such as objectivity, transparency and rationality. The scientific community has made substantial efforts to detect, explicate and critically examine different types of biases (Sackett, 1979; Ioannidis, 2005; Ioannidis, 2018; Macleod et al., 2015). One example of this is the catalogue of all the biases that affect medical evidence compiled by the Centre for Evidence Based Medicine at Oxford University (catalogueofbias.org). Such awareness is commonly seen as a crucial step towards making science objective, transparent and free from bias.

6 0
2 years ago
A solution is made by dissolving 4.0 moles of sodium chloride (NaCl) in 2.05 kilograms of water. If the molal boiling point cons
kozerog [31]
Properties of a solution that depend only on the ratio of the number of particles of solute and solvent in the solution are known as colligative properties. For this problem, we use boiling point elevation concept.

ΔT(boiling point)  = (Kb)mi
ΔT(boiling point)  = (0.51 C-kg / mol )(4.0 mol / 2.05 kg ) (2)
ΔT(boiling point)  = 1.99 C

T(boiling point) = 101.99 C
4 0
3 years ago
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