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Free_Kalibri [48]
3 years ago
7

To produce 40.0 g of silver chromate, you will need at least 23.4 g of potassium chromate in solution as a reactant. All you hav

e on hand in the stock room is 5 L of a 6.00 M K2CrO4 solution. What volume of the solution is needed to give you the 23.4 g K2CrO4 needed for the reaction?
Chemistry
1 answer:
Nata [24]3 years ago
6 0

Answer:

volume of K_2CrO_4 required=20.1 ml

Explanation:

First calculate the number of mole of K_2CrO_4,

given mass of K_2CrO_4=23.4 gram ⇒this is the required mass to produce 40 gram silver chromate

molecular weight=194g/mol

mole=\frac{given \, mass}{molecular\, weight}

mole=0.121 mol

molarity is given and we have also calculated the mole so we will use the relation between molarity,volume and mole i.e.

molarity= \frac{mole}{volume\, in\, L}

6= \frac{0.121}{volume\, in\, L}

volume in L=0.0201 lire

volume of K_2CrO_4 required=20.1 ml

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