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2 years ago

5. What is the overall charge of the electron cloud of the atom?Explain

Chemistry

1 answer:

Basile [38]2 years ago

8 0

The answer is: The overall charge of the electron cloud is negative,

Electron: Electron is a sub-atomic particle which is found outside the nucleus of an atom. The charge carried by an electron is negative.

What is the electron cloud and who suggest this idea?

Erwin Schrödinger developed electron cloud model.
He suggested that atoms have a central nucleus made up of protons and neutrons. Around it is the "probability region" where electrons are most likely to be found.
The higher the density, the more likely the electron will be found in this region.
This dense probability region is called an electron cloud.
As this region carries only negatively charged electrons, thus the overall charge of the electron cloud is negative.

To learn more about electrons and electron cloud, visit:

brainly.com/question/2437516

#SPJ9

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How many kilojoules of energy would be required to heat a 225g block of aluminum from 23.0 C to 73.5 C?

gulaghasi [49]

Answer:

$\boxed {\boxed {\sf 10.2 \ kJ}}$

Explanation:

We are asked to find how many kilojoules of energy would be required to heat a block of aluminum.

We will use the following formula to calculate heat energy.

$q=mc \Delta T$

The mass (m) of the aluminum block is 225 grams and the specific heat (c) is 0.897 Joules per gram degree Celsius. The change in temperature (ΔT) is the difference between the final temperature and the initial temperature.

ΔT = final temperature - inital temperature

The aluminum block was heated from 23.0 °C to 73.5 °C.

ΔT= 73.5 °C - 23.0 °C = 50.5 °C

Now we know all three variables and can substitute them into the formula.

m= 225 g
c= 0.897 J/g° C
ΔT= 50.5 °C

$q= (225 \ g )(0.897 \ J/g \textdegree C)(50.5 \textdegree C)$

Multiply the first two numbers. The units of grams cancel.

$q= (225 \ g * 0.897 \ J/g \textdegree C)(50.5 \textdegree C)$

$q= (225 * 0.897 \ J / \textdegree C)(50.5 \textdegree C)$

$q= (201.825\ J / \textdegree C)(50.5 \textdegree C)$

Multiply again. This time, the units of degrees Celsius cancel.

$q= 201.825 \ J * 50.5$

$q= 10192.1625 \ J$

The answer asks for the energy in kilojoules, so we must convert our answer. Remember that 1 kilojoule contains 1000 joules.

$\frac { 1 \ kJ}{ 1000 \ J}$

Multiply by the answer we found in Joules.

$10192.1625 \ J * \frac{ 1 \ kJ}{ 1000 \ J}$

$10192.1625 * \frac{ 1 \ kJ}{ 1000 }$

$\frac {10192. 1625}{1000} \ kJ$

$10.1921625 \ kJ$

The original values of mass, temperature, and specific heat all have 3 significant figures, so our answer must have the same. For the number we found, that is the tneths place. The 9 in the hundredth place tells us to round the 1 up to a 2.

$10.2 \ kJ$

Approximately <u>10.2 kilojoules</u> of energy would be required.

3 0

3 years ago

______ reactions release energy.

Igoryamba

Combustion reactions release energy in the form of heat.
Hope this helps and tell me if you need more help!

4 0

3 years ago

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nika2105 [10]

Answer:

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Explanation:

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Vladimir79 [104]

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