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aliina [53]
2 years ago
15

5. What is the overall charge of the electron cloud of the atom?Explain

Chemistry
1 answer:
Basile [38]2 years ago
8 0

The answer is: The overall charge of the electron cloud is negative,

Electron: Electron is a sub-atomic particle which is found outside the nucleus of an atom. The charge carried by an electron is negative.

What is the electron cloud and who suggest this idea?

  • Erwin Schrödinger developed electron cloud model.
  • He suggested that atoms have a central nucleus made up of protons and neutrons. Around it is the "probability region" where electrons are most likely to be found.
  • The higher the density, the more likely the electron will be found in this region.
  • This dense probability region is called an electron cloud.
  • As this region carries only negatively charged electrons, thus the overall charge of the electron cloud is negative.

To learn more about electrons and electron cloud, visit:

brainly.com/question/2437516

#SPJ9

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El órgano interno más grande es el hígado. Pero el órgano externo más grande es la piel, <span>Espero que esto ayudó!</span>
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In November 1987, a massive iceberg broke loose from the antartic ice mass and floated free in the ocean. The chunk of ice was e
il63 [147K]
<h2>Answer:</h2>

1.58  × 10∧16 pools.

<h3>Explanation:</h3>

Given:

Length of ice berg= 98 miles = 1557716 meters

Width of iceberg = 25 miles = 40233.6 meters

Thickness of iceberg = 750 ft = 230 meters

Volume of water in a swimming pool = 24,000 gallons = 90850 liters

The volume of the ice berg:

Volume = Length . width . thickness

Volume = 1557716 . 40233.6 . 230 = 1,441, 468, 016, 5248 m3 =  1,441, 468, 016, 5248 × 10 ∧3 L.

1 pool contains liters of water:  90850 liters

1,441, 468, 016, 5248 × 10 ∧3 liters contains = 1/90850 . 1,441, 468, 016, 524.8 × 10 ∧3 .

= 1.100 .  1,441, 468, 016, 5248 × 10 ∧3 L.

= 1.58  × 10∧16 pools.

Hence 1.6 × 10∧16 pools will be filled with that chunk of ice.


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How many chiral centres are there in warfarin molecule?
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I'm actually not sure... but maybe this will help!
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