Given the following phasors and the information related to the frequency of that phasor, provide the corresponding time-domain r
epresentation. (It is somewhat hard to tell the difference, but the terms on the left are the symbols for the phasor, e.g., V, while the terms in the interior provide the units, e.g., V is volts.) (a) V = 7e jπ/6 V, ω = 100 rad/s (b) V = √ 2e −j0.25 V, f = 100 Hz (c) V = 42 π/6 V, T = 10−6 s (d) I = 17 45◦ A, ω = 2π2 × 103 rad/s (e) I = 7 −π/2 A, f = 0.5 Hz
1 answer:
Answer:
Explanation:
In Engineering and Physics a Phasor That is a portmanteau of phase vector, is a complex number that represents a sinusoidal function whose Amplitude (A), Angular Frequency (ω), and Initial Phase (θ) are Time-invariant.
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Answer:
a) 84.034°C
b) 92.56°C
c) ≈ 88 watts
Explanation:
Thickness of aluminum alloy fin = 12 mm
width = 10 mm
length = 50 mm
Ambient air temperature = 22°C
Temperature of aluminum alloy is maintained at 120°C
<u>a) Determine temperature at end of fin</u>
m = √ hp/Ka
= √( 140*2 ) / ( 12 * 10^-3 * 55 )
= √ 280 / 0.66 = 20.60
Attached below is the remaining answers
Answer:
Outside temperature =88.03°C
Explanation:
Conductivity of air-soil from standard table
K=0.60 W/m-k
To find temperature we need to balance energy
Heat generation=Heat dissipation
Now find the value
We know that for sphere
Given that q=500 W
so
By solving that equation we get
=88.03°C
So outside temperature =88.03°C
