Two bumper cars move in a straight line with the following equations of motion: x1 = -4.0 m + (1.1 m/s )t x2 = 8.8 m + (-2.9 m/s
1 answer:
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Answer:
Option (2)
Explanation:
From the figure attached,
Horizontal component,
= 7.22 m
Vertical component,
= 9.58 m
Similarly, Horizontal component of vector C,
= C[Cos(60)]
= 6[Cos(60)]
=
= 3 m
= 5.20 m
Resultant Horizontal component of the vectors A + C,
m
= 4.38 m
Now magnitude of the resultant will be,
From ΔOBC,
=
=
= 6.1 m
Direction of the resultant will be towards vector A.
tan(∠COB) =
=
=
m∠COB =
= 46°
Therefore, magnitude of the resultant vector will be 6.1 m and direction will be 46°.
Option (2) will be the answer.
