The number of molecules that are in balloon are = 2.227 x10^23 molecules
<h3> calculation</h3>
calculate the number of moles of NO
moles = mass/molar mass
molar mass of NO = 14+ 16 = 30 g/mol
moles is therefore= 11.1 g/30g/mol= 0.37 moles
by use of Avogadro's constant that is
1 mole= 6.02 x10^23 molecules
0.37 =? molecules
=(6.02 x10^23 x 0.37 moles)/ 1mole=2.227 x10^23 molecules
Answer:
35.1 kJ/mol is the expected value for the heat of sublimation of acetic acid.
Explanation:
..[1]
Heat of vaporization of acetic acid = 
..[2]
Heat of fusion of acetic acid = 
Heat of sublimation of acetic acid = 
..[3]
[1] + [2] = [3] (Hess's law)


35.1 kJ/mol is the expected value for the heat of sublimation of acetic acid.
<span>Zn⁰(s) + CuSO4(aq) --> Zn²⁺SO4²⁻(aq) + Cu(s)
</span>Zn⁰ --- in free elements oxidation number is 0.
Zn²⁺SO4²⁻ ---- ionic compound , it has ion Zn²⁺, so oxidation number here is +2.
<span>The oxidation number of Zn changes from 0 to +2.</span>
The mass of copper that will be produced from copper oxide is determined as 3.19 g.
<h3>
Mass of copper produced from copper oxide</h3>
The mass of copper that will be produced from copper oxide is calculated as follows;
2Cu + O₂ -----> 2CuO
2 1 2
2(63.5) ------------ 2(79.5)
x ---------------------- 4 g
x = (4 x 2 x 63.5)/(2 x 79.5)
x = 3.19 g
Thus, the mass of copper that will be produced from copper oxide is determined as 3.19 g.
Learn more about copper here: brainly.com/question/24856041
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Answer:
12.5 g
Explanation:
<em>12.5 g of the compound would be formed.</em>
First, let us look at the balanced equation of reaction.

3 moles of Mg is required to react with 1 mole of N2 to produce 1 mole of product.
<em>Recall that: mole = mass/molar mass</em>
9.03 g of Mg = 9.03/24.3 = 0.3716 mole
3.48 g of N2 = 3.48/28 = 0.1243 mole
Mole ratio of Mg/N2 = 3:1
<em>Hence, there is no limiting reactant.</em>
3 moles of Mg is required for 1 mole of product.
0.3716 mole of Mg will therefore require:
0.3716 x 1/3 = 0.1239 moles of product.
Molar mass of product
= 100.9 g/mol
Mass of 0.1239 mole
= mole x molar mass
= 0.1239 x 100.9 = 12.5 g