Answer:
E = 19.89 × 10⁻¹³ J
Explanation:
Given data:
Wavelength of gamma ray= 1.0× 10⁻¹³ m
Energy of gamma ray = ?
Solution:
Formula:
E = h c/λ
h = plancks constant = 6.63× 10⁻³⁴ js
c = speed of light = 3 ×10⁸ m/s
by putting values,
E = 6.63× 10⁻³⁴ js × 3 ×10⁸ m/s /1.0× 10⁻¹³ m
E = 19.89 × 10⁻²⁶ J.m/ 1.0× 10⁻¹³ m
E = 19.89 × 10⁻¹³ J
<span>The correct answer should be Oak becaue of the climate. Spruces usually grow in places that are really cold, the more north you go the higher the chance of finding a spruce forest. South of it is usually an Oak forest because the climate is warmer and oaks grow in warmer climates that are not as harsh as those with spruces.</span>
Answer:
C. 0.4.
Explanation:
<em>∵ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) = (no. of moles acetic acid)/(no. of moles of acetic acid + no. of moles of water).</em>
<em></em>
- no. of moles of acetic acid = 2, no. of moles of water = 3.
- Total no. of moles = no. of moles of acetic acid + no. of moles of water = 2 + 3 = 5.
<em>∴ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) =</em> (2)/(5)<em> = 0.4.</em>
The initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C
<h3>How to calculate temperature?</h3>
The initial temperature of the copper metal can be calculated using the following formula on calorimetry:
Q = mc∆T
mc∆T (water) = - mc∆T (metal)
Where;
- m = mass
- c = specific heat capacity
- ∆T = change in temperature
According to this question, a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, the initial temperature of the copper is as follows:
400 × 4.18 × (42°C - 24°C) = 240 × 0.39 × (T - 24°C)
30,096 = 93.6T - 2246.4
93.6T = 32342.4
T = 345.5°C
Therefore, the initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C.
Learn more about temperature at: brainly.com/question/15267055
