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Soloha48 [4]
4 years ago
9

Describe how the intensity of light changes with distance from a light source.

Physics
1 answer:
lions [1.4K]4 years ago
6 0

Answer:

decreases

Explanation:

The intensity of light is inversely proportional to the square of distance between the source and the observation point.

Intensity \propto \frac{1}{distance^{2}}

So, as the distance increases by the factor of 2, then intensity becomes one fourth.

As the distance becomes half, the intensity becomes four times,

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Can yall help me? itsmy exam quetion!!!!
GarryVolchara [31]

Answer:

Well, to be perfectly honest in my humble opinion, of course without offending anyone who thinks different from my point of view but also by looking into this matter in a different perspective and without condemning one's view and by trying to make it objectified and considering each and everyone's valid opinion, I honestly believe that I completely forgot what I was going to say.

8 0
3 years ago
If a tube is placed vertically into a container of water, and the water level inside the tube is the same as the water level on
dybincka [34]
It's equal to d external atmospheric pressure
6 0
3 years ago
(a) In the baggage claim area of an airport, a particular baggage carousel is shaped like a section of a large cone, steadily ro
Tom [10]

Answer:

Part a)

F_f = 107.8 N

Part b)

\mu = 0.415

Explanation:

Part a)

Time period of one revolution is given as

T = 42 s

now the angular speed of the belt is given as

\omega = \frac{2\pi}{T}

\omega = \frac{2\pi}{42}

\omega = 0.15 rad/s

Now at rest position the force along the surface of carousel must be constant

so we will have

mgsin\theta + m\omega^2 r cos\theta = F_f

30(9.81)sin20.5 + 30(0.15^2)(7.46)cos20.5 = F_f

F_f = 107.8 N

Part b)

New Time period of one revolution is given as

T = 30 s

now the angular speed of the belt is given as

\omega = \frac{2\pi}{T}

\omega = \frac{2\pi}{30}

\omega = 0.21 rad/s

Now at rest position the force along the surface of carousel must be constant

so we will have

mgsin\theta + m\omega^2 r cos\theta = F_f

30(9.81)sin20.5 + 30(0.21^2)(7.94)cos20.5 = F_f

F_f = 112.9 N

Also we know that in perpendicular direction also force is balanced

F_n + m\omega^2 r sin\theta = mgcos\theta

F_n = mgcos\theta - m\omega^2 r sin\theta

F_n = 30(9.81)cos20.5 - 30(0.21)^2(7.94)sin20.5

F_n = 272 N

now for friction coefficient we will have

F_f = \mu F_n

112.9 = \mu 272

\mu = 0.415

8 0
3 years ago
A diagram that show the sun and the center of the solar system is known as a(n)?
SCORPION-xisa [38]

The answer to this question is B....hope this helps.

4 0
4 years ago
The sun's properties (luminosity, size, and temperature) have not changed much over the last 4.6 billion years. what do you thin
Vikentia [17]

The answer is; The sun will turn into a red giant


This occurs as the hydrogen fuel in the fusion core of the sun begins to deplete. When the hydrogen fuel is depleted, the star begins to collapse on itself due to gravity. This pressure causes the heavier helium to begin fusing in the area around the core.  The stars begin to heat up again producing enough energy to push out the outer shells of the star. This causes the star to expand. The outer shells become less hot hence the decrease in luminosity of red giants.


6 0
3 years ago
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