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Soloha48 [4]
3 years ago
9

Describe how the intensity of light changes with distance from a light source.

Physics
1 answer:
lions [1.4K]3 years ago
6 0

Answer:

decreases

Explanation:

The intensity of light is inversely proportional to the square of distance between the source and the observation point.

Intensity \propto \frac{1}{distance^{2}}

So, as the distance increases by the factor of 2, then intensity becomes one fourth.

As the distance becomes half, the intensity becomes four times,

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In the circuit shown below, 0.25 A of current flows through a 20-Ω resistor. How much voltage is needed to produce this current?
balu736 [363]

Answer:

D 5 V

Explanation:

Without seeing the whole circuit it is impossible to say for certain.

However the simplest circuit would produce a value of

FV = IR = 0.25(20) = 5 v

5 0
3 years ago
A load of 54 N attached to a spring that ishanging vertically stretches the spring 0.15 m.What is the spring constant?Answer in
beks73 [17]

Answer:

300 N/m

Explanation:

given,

Load attached to the spring, W = 54 N

length of stretch of the spring, x = 0.15 m

spring constant= ?

Force applied on the spring is calculated by the equation

F = k x

where k is the spring constant

x is the displacement of the spring due to applied load

now,

54 = k × 0.15

k = \dfrac{54}{0.15}

k =300\ N/m

hence, the spring constant is equal to 300 N/m

8 0
3 years ago
Read 2 more answers
A circuit has a resistance of 10ohmsband a current of 42 amps.caculate the voltage
Anon25 [30]
R=U/I so
U=RxI
U= 10 x 42
U= 420 volts
3 0
3 years ago
in the circuit diagram below, three identical light bulbs are connected to a battery. what happens to the brightness of bulb 1 w
andrezito [222]

Answer:

The brightness of bulb 1 dies because it is switched off.

6 0
3 years ago
Class II levers like ankles and wheelbarrows are useful because they provide mechanical advantage, by amplifying the input force
marusya05 [52]

Answer:

The solution and the explanation are in the Explanation section.

Explanation:

According to the diagram that is in the attached image, the EFFORT force at point A and the load is at O point. The torque due to weight is:

TA = W * (a * cosθ)

The torque due to effort at C point is:

TC = E * (b * cosθ)

The net torque is equal to 0, we have:

Tnet = 0

W * (a * cosθ) - E * (b * cosθ) = 0

E=W\frac{a}{b}

From the figure, you can observe that a/b < 1, thus E < W

8 0
3 years ago
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