Answer:
a) Molar fraction:
Methane: 67,5%
Ethane: 25,1%
Propane: 7,4%
b) Molecular weight of the mixture: 25,16 g/mol
Explanation:
with a basis of 100 kg:
Moles of methane:
500 g × = 31,2 moles
Mass of ethane
350 g × = 11,6 moles
Mass of propane
150 g × = 3,4 moles
Total moles: 31,2 moles + 11,6 moles + 3,4 moles = <em>46,2 moles</em>
Molar fraction of n-methane:
=67,5%
Molar fraction of ethane:
= 25,1%
Molar fraction of propane:
= 7,4%
b) Average molecular weight:
= <em>25,16g/mol</em>
I hope it helps!
Answer:
2.5 mL of 1.0 x 10⁻⁴ M solution needs to be added
Explanation:
M₁ (Molarity after dilution) = 1.0 x 10⁻⁵ M
V₁ (volume after dilution) = 25.0 mL
M₂ (molarity before dilution) = 1.0 x 10⁻⁴ M
dilution equation is written as M₁V₁ = M₂V₂
Making V₂ the subject of formula
V₂ = M₁V₁ / M₂
Substitute the parameters in the equation,
V₂ = 1.0 x 10⁻⁵ x 25.0 / 1.0 x 10⁻⁴
= 2.5 mL
Volume of the solution before dilution is 2.5 mL
Repeat same step for the next
From the calculations, we can see that the pH of the solution is 2.3
<h3>What is Kb?</h3>
The term Kb is know as the base dissociation constant. It gives the extent to which a base dissociates in solution.
Hence;
Ka = Kw/Kb = 1 * 10^-14/ 9.88 x 10-8 = 1 * 10^ -7
We have to set up the ICE table;
NH4^+(aq) + H2O(l)⇔ H3O^+(aq) + NH3(aq)
I 2.55 0 0
C -X +X +X
E 2.55 - x x x
Ka = [H3O^+] [NH3]/[NH4^+]
1 * 10^ -7 = x^2/2.55 - x
1 * 10^ -7 (2.55 - x) = x^2
x^2 - 2.55 * 10^ -7 + 1 * 10^ -7x = 0
x=0.0005 M
So; [H3O^+] = [NH3] = 0.0005 M
pH = -log(0.0005 M) = 2.3
Learn more about pH:brainly.com/question/15289741
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Two eukaryotic animal cell organelles that have roles
similar to the organs of the human digestive system are lysosome and
mitochondria. The lysosome is like our stomach, it is responsible for digesting
or breaking down the food consumed by the cell. Mitochondria is like the small
intestine, it is responsible for converting the food we eat into nutrients and
minerals needed for the cell.
Chromatography hope it works!