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MA_775_DIABLO [31]
3 years ago
7

If I titrate an acid with 255mL of 3.4 M NaOH (base) and reach the equivalence point, how many moles of H+ ions were in the acid

?
Chemistry
1 answer:
FromTheMoon [43]3 years ago
7 0

Answer:

Molar Concentration = \frac{Moles of Solute}{Litres of Solution}

                                     = \frac{3.4}{0.255}

                                    =  13.33

No. of H+ ions present = 13.33

pH value = - log[13.33]

               =  -1.12

Explanation:

The equivalence point, or stoichiometric point, of a substance response is the point at which synthetically identical amounts of reactants have been blended. As such, the moles of corrosive are equal to the moles of base, as per the condition (this doesn't really infer a 1:1 molar proportion of acid:base, simply that the proportion is equivalent to in the condition). It tends to be found by methods for a marker, for instance phenolphthalein or methyl orange. The endpoint (identified with, however not equivalent to the equivalence point) alludes to the point at which the marker changes shading in a colorimetric titration.

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The mass fractions of a mixture of gases are 15 percent nitrogen, 5 percent helium, 60 percent methane, and 20 percent ethane wi
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Explanation:

mass fraction N₂ : He : CH₄ : C₂H₆ : : 15 : 5 : 60 : 20

mole fraction  N₂ : He : CH₄ : C₂H₆ : : 15/28 : 5/4 : 60/16 : 20/30

mole fraction  N₂ : He : CH₄ : C₂H₆ : : .5357  : 1.25 : 3.75 : .67

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Partial pressure of He = 1200 kPa  x .20  = 240 kPa

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Partial pressure of C₂H₆ = 1200 kPa  x .108    = 129.6 kPa

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