Answer:
............................................................................
Explanation:
If I titrate an acid with 255mL of 3.4 M NaOH (base) and reach the equivalence point, how many moles of H+ ions were in the acid
1 answer:
Answer:
Molar Concentration =
=
= 13.33
No. of H+ ions present = 13.33
pH value = - log[13.33]
= -1.12
Explanation:
The equivalence point, or stoichiometric point, of a substance response is the point at which synthetically identical amounts of reactants have been blended. As such, the moles of corrosive are equal to the moles of base, as per the condition (this doesn't really infer a 1:1 molar proportion of acid:base, simply that the proportion is equivalent to in the condition). It tends to be found by methods for a marker, for instance phenolphthalein or methyl orange. The endpoint (identified with, however not equivalent to the equivalence point) alludes to the point at which the marker changes shading in a colorimetric titration.
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Answer:
0.13 m of → Highest boiling point
0.19 m of → Second Highest boiling point
0.17 m of → Third highest boiling point
0.31 m Sucrose (nonelectrolyte) → Lowest boiling point
Explanation:
Elevation in boiling is given by :
Where :
i = van't Hoff factor
= Molal Elevation constant of solvent
m = molaity of the solution
1) 0.19 m of
i = 2 (electrolyte)
Molality of the solution = 0.19
Elevation is boiling point of solution:
2) 0.17 m of
i = 2 (electrolyte)
Molality of the solution = 0.17
Elevation is boiling point solution :
3) 0.13 m of
i = 3 (electrolyte)
Molality of the solution = 0.13
Elevation is boiling point solution :
4) 0.31 m Sucrose (nonelectrolyte)
i = 1 ( non electrolyte)
Molality of the solution = 0.31 m
Elevation is boiling point solution :
Higher the value of elevation in temperature higher will be the boiling point of the solution .
The decreasing order of solution from highest boiling point to lowest boiling point is :
0.13 m of → Highest boiling point
0.19 m of → Second Highest boiling point
0.17 m of → Third highest boiling point
0.31 m Sucrose (nonelectrolyte) → Lowest boiling point
Answer:
N,N-dimethylacetamide is formed.
Explanation:
- It is an example of a nucleophilic addition-elimination reaction. Here dimethylamine acts as a nucleophile.
- In the first step, dimethyl amine gives nucleophilic addition reaction at carbonyl center of acetyl chloride.
- In the second step, removal of Cl atoms occurs.
- In the third step, deprotonation takes place from amino group to produce N,N-dimethylacetamide.
- Full reaction mechanism has been shown below.
