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andrey2020 [161]
4 years ago
10

For a certain interval of time, an object is acted on by a constant non-zero force. Which of the following statements is true fo

r this interval of time? (Select all that apply.)
A. The object is at rest.
B. The object's velocity changes.
C. The object's velocity can only increase.
D. The object is moving with constant velocity.
E. The object is accelerating.
Physics
2 answers:
aleksklad [387]4 years ago
8 0

For a certain interval of time, an object is acted on by a constant non-zero force. For this interval of time . . . . .

A. The object is at rest.  No. From F=ma, if F is not zero, the object can't remain at rest.

<em>B.</em> <em>The object's velocity changes.</em> <em>Yes.</em> From F=ma, if F is not zero, there must be acceleration.

C. The object's velocity can only increase.  No. It might decrease.

D. The object is moving with constant velocity.  No. From F=ma, if F is not zero, there must be acceleration.

<em>E.</em> <em>The object is accelerating.</em> <em>Yes.</em> From F=ma, if F is not zero, there must be acceleration.

Anna [14]4 years ago
3 0
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Two trains on separate tracks move toward each other. Train 1 has a speed of 109 km/h; train 2, a speed of 99.0 km/h. Train 2 bl
Rufina [12.5K]

Answer:

f_o=592.36 Hz

Explanation:

Given that

Train 1 (observer):

Speed = 109 km/h

Train 2 (source):

Speed = 99 km/h

Train 2 emitting frequency = 500 Hz

We know that observer and source are moving toward each other, then frequency heard by observer can be given as follows

f_o=\left(\dfrac{C+V_o}{C-V_s}\right)f_s

Where C is the velocity of sound  (C=1225 Km/h)

Now by putting the values

f_o=\left(\dfrac{C+V_o}{C-V_s}\right)f_s

f_o=\left(\dfrac{1225+109}{1225-99}\right)\times 500

f_o=592.36 Hz

4 0
3 years ago
Two straight wires are in parallel and carry electrical currents in opposite directions with the same magnitude of 2.0A. The dis
Veronika [31]

Answer:

Explanation:

Two straight wires

Have current in opposite direction

i1=i2=i=2Amps

Distance between two wires

r=5mm=0.005m

Length of one wire is ∞

Length of second wire is 0.3m

Force between the wire,

The force between two parallel currents I1 and I2, separated by a distance r, has a magnitude per unit length given by

F/l = μoi1i2/2πr

F/l=μoi²/2πr

μo=4π×10^-7 H/m

The force is attractive if the currents are in the same direction, repulsive if they are in opposite directions.

F/l = μoi1i2/2πr

F/0.3=4π×10^-7×2²/2π•0.005

F/0.3=1.6×10^-4

Cross multiply

F=1.6×10^-4×0.3

F=4.8×10^-5N

3 0
4 years ago
Choose the description for a star cluster.
luda_lava [24]

Answer:

It is number two

Explanation:

beacause a star cluster is a bunch of stars held together by gravity

5 0
3 years ago
A cyclotron is designed to accelerate protons (mass 1.67 x 10^-27 kg) up to a kinetic energy of 2.5 x 10^-13 J. If the magnetic
Dafna11 [192]

Answer:

24 cm

Explanation:

Given:

Mass of proton = 1.67 × 10⁻²⁷ Kg

kinetic energy = 2.5 × 10⁻¹³ J

magnetic field in the cyclotron, B = 0.75 T

Now,

Kinetic energy = \frac{1}{2}mv^2  = 2.5 × 10⁻¹³ J

where, v is the velocity of the electron

or

\frac{1}{2}\times1.67\times10^{-27}\times v^2  = 2.5 × 10⁻¹³ J

or

v² = 2.99 × 10¹⁴

or

v = 1.73 × 10⁷ m/s

also,

centripetal force = magnetic force

or

\frac{mv^2}{r}  = qvB

q is the charge of the electron

r is the radius of the dipole magnets

on substituting the respective values, we get

\frac{1.67\times10^{-27}\times1.73\times10^7}{r}  = 1.6 × 10⁻¹⁹ × 0.75

or

r = 0.2408 m ≈ 24 cm

Hence, the correct answer is 24 cm

6 0
3 years ago
A bowling ball of mass 8 kg hits a wall going 5 m/s and rebounds at a speed of 4 m/s. What was the impulse applied to the bowlin
monitta
Yo, sorry I just resized I am so dumb.

The Answer would be C.

Becuase the wall is pushing off 9 becuase it took 5 and bounced back off 4 so 

9 times 8= 72 kg m/s 

Sorry about that ):

7 0
3 years ago
Read 2 more answers
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