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andrey2020 [161]
3 years ago
10

For a certain interval of time, an object is acted on by a constant non-zero force. Which of the following statements is true fo

r this interval of time? (Select all that apply.)
A. The object is at rest.
B. The object's velocity changes.
C. The object's velocity can only increase.
D. The object is moving with constant velocity.
E. The object is accelerating.
Physics
2 answers:
aleksklad [387]3 years ago
8 0

For a certain interval of time, an object is acted on by a constant non-zero force. For this interval of time . . . . .

A. The object is at rest.  No. From F=ma, if F is not zero, the object can't remain at rest.

<em>B.</em> <em>The object's velocity changes.</em> <em>Yes.</em> From F=ma, if F is not zero, there must be acceleration.

C. The object's velocity can only increase.  No. It might decrease.

D. The object is moving with constant velocity.  No. From F=ma, if F is not zero, there must be acceleration.

<em>E.</em> <em>The object is accelerating.</em> <em>Yes.</em> From F=ma, if F is not zero, there must be acceleration.

Anna [14]3 years ago
3 0
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If the magnification is - 0.6

mag = v/u = -0.5

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Substitute u = -20cm ( due to negative magnification)and v = 10cm into the lens formula to get the focal length f

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{-1+2}{20} \\\frac{1}{f} = \frac{1}{20} \\cross \ multiply\\f = 20\\f = 20 cm

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7 0
3 years ago
The capacitor can withstand a peak voltage of 590 volts. If the voltage source operates at the resonance frequency, what maximum
kirill115 [55]

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f=\dfrac{1}{2\pi\sqrt{LC}}

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f=\dfrac{1}{2\pi\sqrt{0.380\times1.20\times10^{-8}}}

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Using formula of current

I=\dfrac{V_{c}}{X_{c}}

I=2\pi\times f\times C\times V_{c}

I=2\pi\times2356.88\times1.20\times10^{-8}\times590

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z=\sqrt{R^2+(X_{L}^2-X_{C}^2)}

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