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3 years ago

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A 5000kg freight car moving at 2 m/s East collides with a 10,000kg freight car at rest. Upon collision, they got stuck and moved

with same velocity. Find their final velocity after collision

1 answer:

mr_godi [17]3 years ago

6 0

Answer:

A

Explanation:

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The term yoga means which of the following:

hjlf

The answer is A: to relax & meditate

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3 years ago

Read 2 more answers

Which evidence would confirm that a given rock later is newer than the layers around it. 1. It has been crumpled in folded, whil

s344n2d4d5 [400]

Answer:

Option 2. It cuts through all the other layers

Explanation:

Newer or younger rocks are usually formed from older rocks in the sense that older rocks are broken up, and their by product materials forming together to make younger rocks.

We can simply say that older rocks basically undergo recycling to form newer rocks.

Thus, looking at the given options,

For option 1, the newer rock cannot be crumpled while the others lie flat because it is the old one that is undergoing recycling and therefore the older one is the one that will be crumpled to give way for newer rocks. So it's not true.

For option 2, since they are from older rocks, they will clearly cut through the other layers of the old one because the old one will give way for the new one.

Option 3 is not true for the same reason given for option 1.

Option 4 is not true because there is no standard way in which it will be positioned

5 0

3 years ago

Normal atmospheric pressure at sea level is ?

iris [78.8K]

1 bar or 100 000 pascales. Or 1020 hPa. It kinda differentiates.

5 0

3 years ago

A small remote-control car with a mass of 1.65 kg moves at a constant speed of v = 12.0 m/s in a vertical circle inside a hollow

Reil [10]

Answer:

$N=63.69N$

Explanation:

The normal force exerted on the car by the walls of the cylinder at the bottom of the vertical circle will be such that when substracted to the weight it must give the centripetal force, since at that point on the vertical $F_{cp}=N-W=N-mg$

We also know that the equation for the centripetal force is:

$F_{cp}=ma_{cp}=\frac{mv^2}{r}$

Mixing both equations we get:

$N-mg=\frac{mv^2}{r}$

$N=mg+\frac{mv^2}{r}$

Which for our values means:

$N=(1.65Kg)(9.8m/s^2)+\frac{(1.65Kg)(12m/s)^2}{(5m)}=63.69N$

8 0

3 years ago

A mass m at the end of a spring vibrates with a frequency

Wittaler [7]

Answer:

m = 0.59 kg.

Explanation:

First, we need to find the relation between the frequency and mass on a spring.

The Hooke's law states that

$F = -kx$

And Newton's Second Law also states that

$F = ma = m\frac{d^2x}{dt^2}$

Combining two equations yields

$a = -\frac{k}{m}x$

The term that determines the proportionality between acceleration and position is defined as angular frequency, ω.

$\omega = \sqrt{\frac{k}{m}}$

And given that ω = 2πf

the relation between frequency and mass becomes

$f = \frac{1}{2\pi}\sqrt{\frac{k}{m}}$ .

Let's apply this to the variables in the question.

$0.88 = \frac{1}{2\pi}\sqrt{\frac{k}{m}}\\0.60 = \frac{1}{2\pi}\sqrt{\frac{k}{m+0.68}}\\\frac{0.88}{0.60} = \frac{\frac{1}{2\pi}\sqrt{\frac{k}{m}}}{\frac{1}{2\pi}\sqrt{\frac{k}{m+0.68}}}\\1.4667 = \frac{\sqrt{m+0.68}}{\sqrt{m}}\\2.15m = m + 0.68\\1.15m = 0.68\\m = 0.59~kg$

6 0

3 years ago