Answer:
double replacement
Explanation:
The reaction shown is a double replacement reaction.
It is also known as double decomposition or metathesis reaction.
In such a reaction, there is an actual exchange of partners to form new compounds.
One of the following is the driving force for such reaction:
- formation of an insoluble compound or precipitate
- formation of water or any other non-ionizing compound
- liberation of a gaseous product.
Answer:
The molarity of urea in this solution is 6.39 M.
Explanation:
Molarity (M) is <em>the number of moles of solute in 1 L of solution</em>; that is

To calculate the molality, we need to know the number of moles of urea and the volume of solution in liters. We assume 100 grams of solution.
Our first step is to calculate the moles of urea in 100 grams of the solution,
using the molar mass a conversion factor. The total moles of 100g of a 37.2 percent by mass solution is
60.06 g/mol ÷ 37.2 g = 0.619 mol
Now we need to calculate the volume of 100 grams of solution, and we use density as a conversion factor.
1.032 g/mL ÷ 100 g = 96.9 mL
This solution contains 0.619 moles of urea in 96.9 mL of solution. To express it in molarity, we need to calculate the moles present in 1000 mL (1 L) of the solution.
0.619 mol/96.9 mL × 1000 mL= 6.39 M
Therefore, the molarity of the solution is 6.39 M.
Yes, it will be worthwhile to investigate finding a catalyst to use in this reaction under standard conditions because it is negative.
<h3>What is a Catalyst?</h3>
This is a substance which speeds up the rate of a chemical reaction by lowering the activation energy.
ΔG being negative indicates a a slow reaction which is why a catalyst under standard conditions should be used.
Read more about Catalyst here brainly.com/question/12507566
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