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2 years ago

7

How much voltage is required to run 1.6 A of current through a 240

1 answer:

pentagon [3]2 years ago

6 0

Answer:

answer is not there

Explanation:

V=1.6×240

V=384volt

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A gas is located inside a closed container. if the gas is allowed to occupy more volume inside the container, what will happen t

nataly862011 [7]

Pressure in the container will decrease.

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3 years ago

The table below shows the content in mg of some chemical elements found in 100g of milk:

garri49 [273]

Answer:

... chloride, calcium, potassium, and zinc was signifi- ... of cow and goat milk pasteurization on element retention ... certified American Chemical Society (ACS);. Whatman ... goat milk. Table 2 gives the content of 17 elements of ... found .0026 rag/100 g in raw and .0024 mg/100 ... mg/100 g chloride content (27) and another.

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3 years ago

Day and night are caused by what

Aleks04 [339]

Answer:

THE GOD ALMIGHTY!

Explanation:

6 0

3 years ago

10 points!! Please give me work with it and I will mark as brainlist.

Georgia [21]

Answer: The molecular formula will be $C_2H_4O_2$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 40.0 g

Mass of O = 53.3 g

Mass of H = 6.66 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{40.0g}{12g/mole}=3.33moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{53.3g}{16g/mole}=3.33moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.66g}{1g/mole}=6.66moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{3.33}{3.33}=1$

For O = $\frac{3.33}{3.33}=1$

For H = $\frac{6.66}{3.33}=2$

The ratio of C : O : H = 1: 1: 2

Hence the empirical formula is $COH_2$

The empirical weight of $COH_2$ = 1(12)+1(16)+2(1)= 30g.

The molecular weight = 60 g/mole

Now we have to calculate the molecular formula.

$n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{60}{30}=2$

The molecular formula will be= $2\times CH_2O=C_2H_4O_2$

8 0

2 years ago

A student finds a container of gases in the laboratory classroom with a total pressure reading of 655 mmHg. The label on the con

Elena-2011 [213]

Answer:

70.8 mmHg

Explanation:

To find partial pressure of carbon dioxide we first find the mole fraction of carbon dioxide

n (carbon dioxide) = 5/44.01 g/mol = 0.11361 mol

n (Helium) = 3.75 g/4 g/mol = 0.9375 mol

The partial pressure of carbon dioxide will be the mole fraction of carbon dioxide multiplied by the total pressure

Partial pressure = 0.11361g/(0.11361g + 0.9375 g)* 655 mmHg

= 70.8 mmHg

6 0

3 years ago