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3 years ago

PLEASE HELP!!! ILL GIVE BRANLIEST EXTRA POINTS dont skip :((

Engineering

2 answers:

zubka84 [21]3 years ago

6 0

Answer:

Routine

Explanation:

Loop Structures — The Method Of Repeating Routines In Statements. Repetition of code are called loops, and they are defined as statements that execute lines of code (or routines) repeatedly according to conditions or iterations. ... Take for example a routine that must write as output the string “Hello” 40 times

Nat2105 [25]3 years ago

4 0

Explanation:

Dora is shopping!!! yayayyayaysyayyayayayayayyayayayayysya

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Drum brakes are usually designed so that the condition of the lining can be checked even if the drum has not been

artcher [175]

Answer:

no it has to be removed

Explanation:

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3 years ago

Which one is suitable for industries petrol engine or diesel engine and why?

klio [65]

Answer:

diesel engine

Explanation:

because diesel is stronger than petrol

3 0

3 years ago

Read 2 more answers

1.0•10^-10 standard form

Drupady [299]

Answer:

$1.0 * 10^{-10} = 0.0000000001$

Explanation:

Given

$1.0 * 10^{-10}$

Required

Convert to standard form

$1.0 * 10^{-10}$

From laws of indices

$a^{-x} = \frac{1}{a^x}$

So, $1.0 * 10^{-10}$ is equivalent to

$1.0 * 10^{-10} = 1.0 * \frac{1}{10^{10}}$

$1.0 * 10^{-10} = 1.0 * \frac{1}{10}* \frac{1}{10}* \frac{1}{10}* \frac{1}{10}* \frac{1}{10}* \frac{1}{10}* \frac{1}{10}* \frac{1}{10}* \frac{1}{10}* \frac{1}{10}$

$1.0 * 10^{-10} = 1.0 * \frac{1}{10000000000}$

$1.0 * 10^{-10} = 1.0 * 0.0000000001$

$1.0 * 10^{-10} = 0.0000000001$

Hence, the standard form of $1.0 * 10^{-10}$ is $0.0000000001$

3 0

3 years ago

The Role of Fuel Cells in Renewable Energy Solutions

gogolik [260]

Answer:

chemical energy directly

4 0

3 years ago

We can model a certain battery as a voltage source in series with a resistance. The open-circuit voltage of the battery is 10 V

Angelina_Jolie [31]

Answer:

51.4 Ohms

Explanation:

By applying voltage division rule

$V_f=v_i\times \frac {R_l}{R_l+R_m}$ where v is voltage, subscripts i and f represnt initial and final, R is resistance, m is internal and l is external.Substituting 7V for final voltage, 10V for initial voltage and the external resistance as 120 Ohms then

$7=10*\frac {120}{120+R_m}\\7R_m+840=1200\\R_m={1200-840}{7}=51.428571\approx 51.4 Ohms$

3 0

3 years ago

PLEASE HELP!!! ILL GIVE BRANLIEST *EXTRA POINTS* dont skip :((

PLEASE HELP!!! ILL GIVE BRANLIEST EXTRA POINTS dont skip :((