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2 years ago

PLEASE HELP!!! ILL GIVE BRANLIEST EXTRA POINTS dont skip :((

Engineering

2 answers:

zubka84 [21]2 years ago

6 0

Answer:

Routine

Explanation:

Loop Structures — The Method Of Repeating Routines In Statements. Repetition of code are called loops, and they are defined as statements that execute lines of code (or routines) repeatedly according to conditions or iterations. ... Take for example a routine that must write as output the string “Hello” 40 times

Nat2105 [25]2 years ago

4 0

Explanation:

Dora is shopping!!! yayayyayaysyayyayayayayayyayayayayysya

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Some extremely hazardous materials used in welding operations include.

enyata [817]

Many of the substances in welding smoke, such as chromium, nickel, arsenic, asbestos, manganese, silica, beryllium, cadmium, nitrogen oxides, phosgene, acrolein, fluorine compounds, carbon monoxide, cobalt, copper, lead, ozone, selenium, and zinc, can be extremely toxic.

3 0

2 years ago

Part of a control linkage for an airplane consists of a rigid member CB and a flexible cable AB Originally the cable is unstretc

AnnZ [28]

Answer:

$e_{ab} = 4.18*10^(-3)$

Explanation:

This question will be solved with the help of diagram (see attachment)

Given:

Δ∅ = 0.50 degrees (correction)

BC = 800 mm

AC = 600 mm

Solution:

We use coordinate system with point C as origin (0,0)

Hence,

Point A = (600,0)

Point B = (0,800)

The change in length or displacement can be calculated BB' :

BB' = BC * tan (Δ∅) = (800 mm) * tan (0.5) = 6.9815 mm

Hence, Point B' = (-6.9815,800) and we calculate distance A and B

$AB = \sqrt{600^2 + 800^2} = 1000 mm$

We calculate distance A and B'

$AB' = \sqrt{(600 - (-6.9815))^2 + (0-800)^2} = 1004.2 mm$

Normal Strain in AB is:

$e_{ab} = \frac{AB' - AB}{AB} \\\\= \frac{1004.2 - 1000}{100}\\\\= 4.18 * 10^(-3)$

The solution is :

$e_{ab} = 4.18 * 10^(-3)$

6 0

2 years ago

The specifications of an electronic device are 24 /- 0.4 Amps. When the device exceeds specifications the average quality cost i

Misha Larkins [42]

Answer:

The average loss for this device is $10.90

Explanation:

Given data

Specification = 24 +/- 0.4 Amps

average quality cost = $32.00

average value y = 23.9

standard deviation s = 0.211 Amps

32 = k(24.4 - 24)²

32 = k(0.4)² = k(0.16)

k = 32/0.16 = 200

To evaluate average loss, use

L = k{s² + (y - T)²}

T = 24A

L = 200{0.211² + (23.9 - 24)²}

L = $10.90

The average loss for this device is $10.90

4 0

2 years ago

PLZ ANSWER SOON!!!

slava [35]

Answer:

You're answer would be "D. Perform all of the above"

Explanation:

Have a Blessed Day (Mark Brainliest!)

4 0

2 years ago

Read 2 more answers

Asphalt pavement may achieve temperatures as high as 55°C on a hot summer day. Assume that such a temperature exists throughout

Ganezh [65]

Answer:

-4.99 * 10⁵ J/m²

Explanation:

See attached picture.

6 0

2 years ago

PLEASE HELP!!! ILL GIVE BRANLIEST *EXTRA POINTS* dont skip :((

PLEASE HELP!!! ILL GIVE BRANLIEST EXTRA POINTS dont skip :((