Answer:
242.4 g
Explanation:
RAM of KNO3=39+14+(16×3)=101
Mass=morality×RAM
101*2.4=242.4
The choices can be found elsewhere and as follows:
a. mass-mass problems
<span>b. mass-volume problems </span>
<span>c. mass-particle problems </span>
<span>d. volume-volume problems
</span>
I believe the correct answer is option D. It is volume-volume problems that does not require the use of molar mass. <span> Here you are dealing with molarities and volumes to determine concentrations. Molar mass is not part of any calculations.</span>
Answer:
1. C(2)+H2(1) -> C2H6(1)
2. NH3(2)+O2(3)-> HCN(2)+H2O(3)
I am not sure about the second one.
Answer:
HA + KOH → KA + H₂O
Explanation:
The unknown solid acid in water can release its proton as this:
HA + H₂O → H₃O⁺ + A⁻
As we have the anion A⁻, when it bonded to the cation K⁺, salt can be generated, so the reaction of HA and KOH must be a neutralization one, where you form water and a salt
HA + KOH → KA + H₂O
It is a neutralization reaction because H⁺ from the acid and OH⁻ from the base can be neutralized as water
A. Mutualism. This is because both the larvae and the flower are benefited. The larvae is fed, and the flower is pollinated.
Hope this helps!
