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3 years ago

Why do electrons enter the 4s orbital before entering the 3d orbital?

Chemistry

2 answers:

LUCKY_DIMON [66]3 years ago

8 0

C. Because as it get farther from the nucleus the amount of energy is decreasing

salantis [7]3 years ago

7 0

Answer:

C. because the 4s orbital is at a lower energy level

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How is it possible for there to be more than one kind of atom of the same element?

tiny-mole [99]

They are called isotopes.

Isotopes have the same number of electrons and protons in their unionized state. They differ in the number of neutrons. The first and simplest example is hydrogen.

The most common hydrogen has

1 proton

1 electron and

0 neutrons

It has 2 cousins

1 proton

1 electron

1 neutron

And

1 proton

1 electron

2 neutrons.

Most elements have some differences in the number of neutrons present in their nuclei. Cesium and Xenon have the most number of isotopes. Each has 36. You wonder how the atoms are held together.

6 0

3 years ago

Read 2 more answers

The electron configuration for an atom is 1s 2s 2p2. How many electrons does the atom have?

taurus [48]

Answer:

Four

Step-by-step explanation:

The superscripts in an electron configuration tell us how many electrons are in a subshell.

If the electron configuration is 1s¹ 2s¹2p², the total number of electrons is

1 + 1 + 2 = 4

The atom contains four electrons.

Note: this atom is in an excited state, because the 1s and 2s subshells can each hold one more electron.

7 0

3 years ago

A 7.12 L cylinder contains 1.21 mol of gas A and 4.94 mol of gas B, at a temperature of 28.1 °C. Calculate the partial pressure

GenaCL600 [577]

Answer:

$P_A=4.20atm\\\\P_B=17.1atm$

Explanation:

Hello!

In this case, since the equation for the ideal gas is:

$PV=nRT$

For each gas, given the total volume, temperature (28.1+273.15=301.25K) and moles, we can easily compute the partial pressure as shown below:

$P_A=\frac{n_ART}{V} =\frac{1.21mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_A=4.20atm\\\\P_B=\frac{n_BRT}{V} =\frac{4.94mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_B=17.1atm$

Best regards!

8 0

3 years ago

Select the correct structure that

UkoKoshka [18]

Answer:

ugh this wont save anyway i think i'm just checking if ill save

Explanation:

if i does C both

hope this helps

6 0

2 years ago

Substitute natural gas (SNG) is a gaseous mixture containing CH4(g) that can be used as a fuel. One reaction for the production

Lynna [10]

Answer:

ΔH° of the reaction is -747.54kJ

Explanation:

Based on gas law, it is possible to find the ΔH of a reaction using ΔH of half reactions.

Using the reactions:

(1) C(graphite) + 1/2O₂(g) → CO(g) ΔH° = -110.5 kJ

(2) CO(g) + 1/2O₂(g) → CO₂(g) ΔH° = -283.0 kJ

(3) H₂(g) + 1/2O₂(g) → H₂O(l) ΔH° = -285.8 kJ

(4) C(graphite) + 2H₂(g) → CH₄(g) ΔH° = -74.81 kJ

(5) CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) ΔH° = -890.3 kJ

The sum of 4×(4) + (5) gives:

4C(graphite) + 8H₂(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) + 3CH₄(g)

ΔH° = -74.81 kJ ×4 - 890.3 kJ = -1189.54kJ

Now, this reaction - 4×(1) gives:

4CO(g) + 8H₂(g) → CO₂(g) + 2H₂O(l) + 3CH₄(g)

ΔH° = -1189.54kJ - 4×-110.5 = -747.54kJ

Thus ΔH° of the reaction is -747.54kJ

3 0

3 years ago