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Vsevolod [243]
3 years ago
9

A rocket is launched straight up from the earth's surface at a speed of 1.60×104 m/s . what is its speed when it is very far awa

y from the earth?
Physics
1 answer:
AlladinOne [14]3 years ago
7 0
16,000 m/s
Since it’s speed, and the distance is unknown. Gravity isn’t applying a noticeable force too on the rocket, as if it were, then the rocket would be accelerating negatively.
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Which of these is NOT an example of balanced forces? A. lying still on a bed B. a ship slowly sinking C. leaning against a brick
liraira [26]
<span>B. a ship slowly sinking</span>
This is not balanced
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3 years ago
Read 2 more answers
A 46.0-kg box is being pushed a distance of 8.80 m across the floor by a force P whose magnitude is 171 N. The force P is parall
dolphi86 [110]

Answer:

a) 1504.8 J

b) 991.76 J

c) 0J

d) 0J

Explanation:

(a) The work done by the force P on the box is given by the following formula:

W_P=Px

P: applied force = 171N

x: distance in which the for P is applied = 8.80m

you replace the values of P and x and obtain:

W_P=(171N)(8.80m)=1504.8J

(b) The work don by the friction force is:

W_f=F_fx=\mu N x=\mu Mg x

μ = coefficient of kinetic friction = 0.250

M: mass of the box = 46.0kg

g: gravitational constant = 9.8 m/s^2

W_f=(0.250)(46.0kg)(9.8m/s^2)(8.80m)=991.76J

(c) The Normal force is

N=Mg=(46.0kg)(9,8m/s^2)=450.8N

but this force does not do work on the box because the direction is perpendicular to the direction of the force P.

W_N=0J

(d) the same as before:

W_g=0J

8 0
3 years ago
hink about the friction activity. Return to this activity to see it again if you need to. Explain what happened in each of the t
ankoles [38]
<span>from what i know the force of gravity and its effects on objects, regardless of their mass, fall to the ground at the same rate.</span>
7 0
3 years ago
The mass of the Earth is about 6 x 1024 kg
tia_tia [17]

Well it seems that you did not give answer choices, but that its fine since we can use newtons law of universal gravitational, Fg = GM1M2/r^2. So G is the gravitational constant, which is 6.67*10^-11, we can plug in 6*1024 for M1, and 7*1022 for M2, and 3.8*108 for r. Which then we get 1.74 * 10^8 N as the force of attraction between the Earth and the moon.

3 0
3 years ago
A biker can ride at 12 m/s on a level road when there is no wind and at 7.5 m/s on a level road when there is a head wind of 5 m
alexandr402 [8]

Answer:

The answer is "1.94 \ m^2".

Explanation:

Formula:

F= \frac{1}{2} \times C_D \times density \times area \times  velocity^2\\\\Power (P) = F \times velocity \\\\P = \frac{C_D}{2} \times density \times area \times  velocity^3\\

Given value:

\ P = 10.25 \ W \\\\\ density = 1.2 \ kg/m^3 \\\\\ velocity= 2.5 \\\\

10.25 = \frac{C_D A}{2} \times 1.2 \times 2.5^3\\\\C_D A= \frac{10.25 \times 2 }{1.2 \times 2.5^3}\\\\C_D A = 1.94 m^2\\

8 0
3 years ago
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