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liberstina [14]

3 years ago

11

Physical science tries to a. Survey all of science b. Describe the environment and interaction between living things c. Describe

matter and energy and the relationship between matter and energy d. Describe rocks minerals and resources

1 answer:

RideAnS [48]3 years ago

7 0

Answer:

option "c" is correct

Explanation:

Physical science or Physics is the study of matter, energy and their mutual relationship.

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I need some help with my science homework about energy, work, and power. It would be greatly appreciated :)

fgiga [73]

Answer:

1. B

Explanation:

Work = Force × Distance

Work = 4N × 1.5M

5 0

4 years ago

a certain hydraulic jack is used for lifting load. a force of 250N is applied on a small piston with a diameter of 80cm while th

anzhelika [568]

The maximum mass of a load that can be lifted by the jack and the distance covered are:

m = 160.2 Kg

h = 25 cm

Given that a certain hydraulic jack is used for lifting load. a force of 250N is applied on a small piston with a diameter of 80cm while the diameter of the larger piston is 2.0m.

The parameters given are

$F_{1}$ = 250

$A_{1}$ = Area of the small piston = π $r^{2}$

$A_{1}$ = 22/7 x $0.4^{2}$

$A_{1}$ = 0.5 $m^{2}$

$F_{2}$ = ?

$A_{2}$ = Area of the large piston = π $r^{2}$

$A_{2}$ = π x 1

$A_{2}$ = 3.14 $m^{2}$

To calculate the force on the large piston, we will use the below formula

$F_{1}$ / $A_{1}$ = $F_{2}$ / $A_{2}$

Substitute all the parameters into the equation

250/0.5 = $F_{2}$ /3.14

$F_{2}$ = 1570 N

To calculate the maximum mass of a load that can be lifted by the jack, let us apply Newton second law

F = mg

1570 = 9.8m

m = 1570/9.8

m = 160.2 Kg

.(take g=9.81ms^-2)

If the applied force moves through a distance of 25cm, the distance through which the load is lifted will be

$F_{1}$ / 0.25 $A_{1}$ = $F_{2}$ / $A_{2}$ h

250/0.125 = 1570/3.14h

make h the subject of the formula

6280h = 1570

h = 1570/6280

h = 0.25 m

Therefore, the distance through which the load is lifted is 25 cm

Learn more here: brainly.com/question/13596980

5 0

2 years ago

A series RLC circuit is driven by a 1.0-kHz oscillator. The circuit parameters are Vms = 12 V, L = 5.0 mH, C= 4.0 uF, and R=102.

alexgriva [62]

Answer:

C) $12.3$ volts

Explanation:

f = frequency of oscillator = 1 kHz = 1000 Hz

$V_{rms}$ = 12 Volts

L = Inductance of Inductor = 5 mH = 0.005 H

$X_{L}$ = Inductive reactance

Inductive reactance is given as

$X_{L}$ = $2\pi fL$

$X_{L}$ = $2(3.14) (1000)(0.005)$

$X_{L} = 31.4$

$X_{C}$ = Capacitive reactance

Capacitive reactance is given as

$X_{C}=\frac{1}{2\pi fC}$

$X_{C}=\frac{1}{2(3.14)(1000)(4\times 10^{-6})}$

$X_{C} = 39.8$

Impedance of the circuit is given as

$z = \sqrt{R^{2}+(X_{L} - X_{C})^{2}}$

$z = \sqrt{102^{2}+(31.4 - 39.8)^{2}}$

$z = 102.35$

Rms Current flowing is given as

$i = \frac{V_{rms}}{z}$

$i = \frac{12}{102.35}$

$i = 0.12$ A

Rms potential difference across the resistor is given as

$V = i R$

$V = (0.12) (102)$

$V = 12.3$ volts

5 0

3 years ago

Which of the events below does NOT happen during the G1 phase of the cell cycle

aleksandr82 [10.1K]

Answer:

Could you please add the events

Explanation:

if not I could give a brief explanation of what happens in the phase and you could just eliminate?

6 0

3 years ago

A 5.50 kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the en

11Alexandr11 [23.1K]

Answer:

Explanation:

position

y(t) = 2.80t + 0.61t³

velocity is the derivative of position

v(t) = 2.80 + 1.83t²

acceleration is the derivative of velocity

a(t) = 3.66t

F = ma = 5.50(3.66(4.10)) = 82.533 N

which should be rounded to no more than three significant digits and arguably only two due to the 0.61 factor.

F = 82.5 N or 83 N

Yes the units are Newtons, cannot tell what your system will accept. May not want the units at all.

8 0

3 years ago