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liberstina [14]
2 years ago
11

Physical science tries to a. Survey all of science b. Describe the environment and interaction between living things c. Describe

matter and energy and the relationship between matter and energy d. Describe rocks minerals and resources
Physics
1 answer:
RideAnS [48]2 years ago
7 0

Answer:

option "c" is correct

Explanation:

Physical science or Physics is the study of matter, energy and their mutual relationship.

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Please help me with this and if I have good answer u will be marked as brilliant !!!!
AysviL [449]
Number one- numbers of items sold. Number two- Thursday and Friday. Number three- 1,200. Number four-150
3 0
3 years ago
A satellite is in a circular orbit 8200 km above the Earth’s surface; i.e., it moves on a circular path under the influence of n
andreyandreev [35.5K]

Answer:

5.23km/s

Explanation:

Given

Radius of Earth = 6.37 * 10^6 m

Altitude of Satellite = 8200km = 8200 * 10³m = 8.2 * 10^6 m

Gravity Acceleration on Satellite Altitude = 1.87965m/s²

For a satellite to remain in circular orbit, then it means the acceleration of gravity must be exact as the centripetal acceleration.

Centripetal Acceleration = V²/R

So, Acceleration of Gravity (A)= Centripetal Acceleration = V²/R

Make V the subject of formula

A = V²/R

V² = AR

V = √AR

Where R = (radius of earth) + (altitude of satellite)

R = 6.37 * 10^6 + 8.2 * 10^6

R = 14.57 * 10^6m

A = 1.87965m/s²

V = √(1.87965 * 14.57x10^6)

V = √27386500.5

V = 5233.211299001789

V = 5233.2113 m/s ------- Approximated

V = 5.23km/s

7 0
3 years ago
HELP PLS!<br> (LOOK AT THE PICTURE)
Arturiano [62]
The answer is b !!!! Hope it helps
4 0
2 years ago
Thermal equilibrium is reached when______________.
Art [367]
<span>two objects in contact with each other are the same temperature</span>
4 0
3 years ago
Read 2 more answers
A driver in a 2000 kg Porsche wishes to pass to pass a slow-moving school bus on a four-lane road. What is the average power in
Kryger [21]

The average power is 3.0\cdot 10^6 W

Explanation:

First of all, we calculate the work done to accelerate the car; according to the work-energy theorem, the work done is equal to the change in kinetic energy of the car:

W=K_f -K_i= \frac{1}{2}mv^2-\frac{1}{2}mu^2

where :

K_f = \frac{1}{2}mv^2 is the final kinetic energy of the car, with

m = 2000 kg is the mass of the car

v = 60 m/s is the final speed of the car

K_i = \frac{1}{2}mu^2 is the initial kinetic energy of the car, with

u = 30 m/s is initial speed of the car

Soolving:

W=\frac{1}{2}(2000)(60)^2 - \frac{1}{2}(2000)(30)^2=2.7\cdot 10^6 J

Now we can find the power required for the acceleration, which is given by

P=\frac{W}{t}

where

t = 9 s is the time elapsed

Solving:

P=\frac{2.7\cdot 10^6}{9}=3.0\cdot 10^6 W

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

8 0
3 years ago
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