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sp2606 [1]
3 years ago
9

Match the terms to their descriptions.

Physics
1 answer:
jasenka [17]3 years ago
4 0

Explanation:

1) region outside the nucleus divided into energy levels  : electron cloud

Energy levels are specific spherical orbitals around the nucleus. The region of maximum probability of where an electron is located is called an electron cloud or orbital.

2) located in the outermost energy level, determines how element will react chemically with other elements: valence electrons

Valence electrons are electrons in the outermost energy shell of an atom. They determine whether an atom will react chemically with other elements of not.

3) outermost energy level : valence shell

The valence shell where the outermost electrons are located is the outermost energy level.

4) atoms that have the same number of protons but different numbers of neutrons : isotopes

Isotopes are atoms having the same number of protons but different number of neutrons. They generally have the same chemical properties. They have the same atomic number but different mass number.

5) located in the nucleus, neutral or no charge : neutrons

Neutrons are subatomic particles in the nucleus with no charges on them.

6) located outside the nucleus, negative(-) charge : electrons

Electrons are subatomic particles that carries negative charges

7) located in the nucleus, positive(+) charger: protons

Protons are positive charges in the nucleus of an atom.

learn more:

Atoms brainly.com/question/10216585

#learnwithBrainly

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An object that weighs 2.450 N is attached to an ideal massless spring and undergoes simple harmonic oscillations with a period o
Viktor [21]

Answer:

Spring constant, k = 24.1 N/m

Explanation:

Given that,

Weight of the object, W = 2.45 N

Time period of oscillation of simple harmonic motion, T = 0.64 s

To find,

Spring constant of the spring.

Solution,

In case of simple harmonic motion, the time period of oscillation is given by :

T=2\pi\sqrt{\dfrac{m}{k}}

m is the mass of object

m=\dfrac{W}{g}

m=\dfrac{2.45}{9.8}

m = 0.25 kg

k=\dfrac{4\pi^2m}{T^2}

k=\dfrac{4\pi^2\times 0.25}{(0.64)^2}

k = 24.09 N/m

or

k = 24.11 N/m

So, the spring constant of the spring is 24.1 N/m.

6 0
2 years ago
Name one benefit and one limitation of Comparative investigations
GalinKa [24]
Comparative investigation is a research method that makes comparison across different countries of the world. Limitation : data set in different countries may be defined differently. Benefit : the method is flexible.
8 0
2 years ago
Read 2 more answers
How is energy transformed to chemical energy?
morpeh [17]

it is transfred through the basics

6 0
3 years ago
What was the direction of the ball’s velocity
Tju [1.3M]

Part of the question is missing. Here it is:

<em>A 72 g autographed baseball slides off of a 1.3 m high table and strikes the floor a horizontal distance of 0.7m away from the table.     The acceleration of gravity is 9.81 m/s2. What was the direction of the ball’s velocity  just before it hit the floor? </em>

Answer:

\theta=-75.7^{\circ}

Explanation:

The motion of the ball is a projectile motion, which consists of two separate motions:

- A horizontal motion at constant velocity

- A vertical motion at constant acceleration (free fall)

We start by analyzing the vertical motion, to find the time of flight of the ball. This can be done by using the suvat equation

s=ut+\frac{1}{2}at^2

where, choosing downward as positive direction:

s =1.3 m is the vertical displacement of the ball

u = 0 is the initial vertical velocity

a=g=9.8 m/s^2 is the acceleration of gravity

t is the time

Solving for t,

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(1.3)}{9.8}}=0.52 s

Now we can find the final vertical velocity of the ball, using:

v_y=u+at

And susbtituting t = 0.52 s, we find

v_y = 0 +(9.8)(0.52)=5.1 m/s

It is important to keep in mind that the direction of this velocity is downward, since we chose downward as positive direction.

The horizontal velocity of the ball instead is constant; we know that the ball covers a horizontal distance of

d = 0.7 m

In a time of

t = 0.52 s

So, the horizontal velocity is

v_x = \frac{0.7}{0.52}=1.3 m/s

So now we can find the direction of the ball's velocity using:

\theta=tan^{-1}(\frac{v_y}{v_x})=tan^{-1}(\frac{5.1}{1.3})=75.7^{\circ}

And since the vertical direction is downward, this means that this velocity is below the horizontal, so the answer is

\theta=-75.7^{\circ}

8 0
2 years ago
Our two intrepid relacar drivers are named Pam and Ned. We use these names to make it easy to remember: measurements made by Pam
kenny6666 [7]

This is a problem based on the logic and interpretation of the variables. From the measured data taken

what is collected by the two individuals is expressed as,

- NED reference system: (x, t)

- PAM reference system: (x ', t')

From the reference system we know that ν is the speed of PAM (the other reference system) as a measurement by NED.

Then ν' is the speed of NED (from the other system of the reference) as a measurement by PAM.

8 0
3 years ago
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