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riadik2000 [5.3K]
2 years ago
6

What is speed of light in crown glass?

Physics
1 answer:
german2 years ago
5 0

Answer:

1.97 x 10^8 m/s

Explanation:

refractive index of crown glass with respect to air, n = 1.52

speed of light in air, c = 3 x 10^8 m/s

Let v be the speed of light in crown glass.

By use of the definition of refractive index

n = \frac{c}{v}

where, n be the refractive index of crown glass, c be the speed of light in vacuum and v be the speed of light in crown glass

1.52 = \frac{3 \times 10^{8}}{v}

v = \frac{3 \times 10^{8}}{1.52}

v = 1.97 x 10^8 m/s

Thus, the speed of light in crown glass is 1.97 x 10^8 m/s.

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A small uniform disk and a small uniform sphere are released simultaneously at the top of a high inclined plane, and they roll d
barxatty [35]

Answer:

(D) the sphere

Explanation:

The bodies given are Disk and Solid sphere (uniform sphere)

Moment of inertia of the bodies are

I(disk) = \frac{MR^2}{2}

I(sphere) = \frac{2MR^2}{5}

Since the moment of inertia of sphere is less than that of disk, therefore sphere will reach the bottom first.

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3 years ago
An object is projected straight upward with an initial speed of 25.0 m/s
hoa [83]

Answer:

What's the question your asking?

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It moves with an initial speed of 25.0 miles per second.

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3 years ago
What is the critical angle of a light beam passed from a medium (n=2) to a medium (n=1.2)?
sertanlavr [38]

Answer:

θ_c = 36.87°

Explanation:

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Index of refraction for Refractive medium; n_r = 1.2

Formula to find the critical angle is given;

n_i(sin θ_c) = n_r(sin 90)

Where θ_c is critical angle.

Thus;

2 × (sin θ_c) = 1.2 × 1

(sin θ_c) = 1.2/2

(sin θ_c) = 0.6

θ_c = sin^(-1) 0.6

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8 0
3 years ago
Which formula is used to find fluctuation of the shape of body
Sladkaya [172]

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varn=n1+1ehvkT–1

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A Honda Hawk motorcycle and its rider with a combined mass of 450 kg travels around a curve of radius 106 m with a speed of 18 m
umka21 [38]

Answer: coefficient of static friction

= 0.31

Explanation: Since they negotiate the curve without skidding, the frictional force (F1) equals the centripetal force (F2).

F1= uN

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r is the radius 106m

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Making u subject of the formula we have that,

u = {450*(18²/106)} /4410

=1375.47/4410

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NOTE: coefficient of friction is dimensionless. It as no Unit.

7 0
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