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3 years ago

11

if the net force of 15 N is exerted on an encyclopedia to cause it to accelerate at a rate of 5 m/s2. what is the mass of the en

cyclopedia

1 answer:

Katarina [22]3 years ago

3 0

Answer:

3 kg

Explanation:

F = ma

(15) = m(5)

m = 3 kg

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A charge of -3.02 μC is fixed in place. From a horizontal distance of 0.0377 m, a particle of mass 9.43 x 10^-3 kg and charge -9

Andreyy89

Answer:

$d = 0.0306 m$

Explanation:

Here we know that for the given system of charge we have no loss of energy as there is no friction force on it

So we will have

$U + K = constant$

$\frac{kq_1q_2}{r_1} + \frac{1}{2}mv_1^2 = \frac{kq_1q_2}{r_2} + \frac{1}{2}mv_2^2$

now we know when particle will reach the closest distance then due to electrostatic repulsion the speed will become zero.

So we have

$\frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{0.0377} + \frac{1}{2}(9.43 \times 10^{-3})(80.4)^2 = \frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{r} + 0$

$7.05 + 30.5 = \frac{0.266}{r}$

$r = 7.08 \times 10^{-3} m$

so distance moved by the particle is given as

$d = r_1 - r_2$

$d = 0.0377 - 0.00708$

$d = 0.0306 m$

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3 years ago

Can someone please help me? Will give brainliest.

lora16 [44]

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A 2500-ohm is connected to a 110v power supply. What is the current through the resistor

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Answer:

0.044 amps

Explanation:

Givens

R = 2500 ohms

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I = ?

Equation

I = E/R

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3 years ago

Pierre cycles at 4 miles per hour and travels a distance of 13 miles. How long

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Answer:

His journey took him 3 hours 15 minutes.

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Two people carry a heavy electric motor by placing it on a light board 2.45 m long. One person lifts at one end with a force of

maxonik [38]

Answer:

W=1055N

Explanation:

In order to solve this problem, we must first do a drawing of the situation so we can visualize theh problem better. (See attached picture)

In this problem, we will ignore the board's weight. As we can see in the free body diagram of the board, there are only three forces acting on the system and we can say the system is in vertical equilibrium, so from this we can say that:

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$F_{1}+F_{2}-W=0$

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$W=F_{1}+F_{2}$

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W=410N+645N

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