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liubo4ka [24]
3 years ago
15

What is the slope of the line through (-1,-7) and (3,9)

Mathematics
2 answers:
bazaltina [42]3 years ago
7 0

m=4, therefore your slope is 4.

Steps:

m=y2-y1/x2-x1

Substitute values in:

m= 9-(-7)/3-(-1)

Then just simplify. :)

<em><u>Hope this helps. :)</u></em>

Tju [1.3M]3 years ago
3 0

Answer:

m=4

Step-by-step explanation:

m = change in y/change in x

m = 9-(-7) / 3-)-1)

m= 16 / 4

m = 4 (slope)

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Baker, Inc. uses the sum-of-the-years’-digits method to depreciate a $79,600.00 piece of equipment that has an estimated life of
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Using the sum of the years digits method

Step 1:

We sum up all the digits of the estimated life of equipment.

i.e. 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 210

Step 2:

We count the years spent from the back. i.e. year 2 is equivalent to 19 in the years digits.

Given that the cost of the equipment is $79,600.00 with a salvage value of $4,000.00. This means that the depreciable amount of the equipment is given by $79,600.00 - $4,000.00 = $75,600.00

The depreciation charge on the equipment for year 1 is given by

\frac{20}{210} \times\$75,600=\$7,200

while the depreciation charge on the equipment for year 2 is given by

\frac{19}{210} \times\$75,600=\$6,840

The book value of an equipment is given by the cost of the equipment minus the accumulated depreciation.

Therefore, the book value of the equipment at the end of year 2 is given by

$79,600 - $7,200 - $6,840 = $65,560
6 0
4 years ago
Construct a circle through points<br> X, Y, and Z
d1i1m1o1n [39]

Answer:

Step-by-step explanation:

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3 years ago
How do I do 5/3 to the 3 power
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I hope this helps!!!

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Suppose M is the midpoint of Segment AB, P is the midpoint of Segment AM, and Q is the midpoint of segment PM.
DerKrebs [107]

The coordinates of M, P and Q in terms of a and b are M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b, P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b and Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b, respectively.

In this question we are going to use definitions of vectors and product of a vector by a scalar. Based on the information given on statement, we have the following vectorial formulas:

Location of M

\overrightarrow{AM} = \frac{1}{2}\cdot \overrightarrow{AB}

\vec M - \vec A = \frac{1}{2}\cdot \vec B - \frac{1}{2}\cdot \vec A

\vec M = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec B

M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b

Location of P

\overrightarrow{AP} = \frac{1}{2}\cdot \overrightarrow{AM}

\vec P - \vec A = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec A

\vec P = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec M

\vec P = \frac{3}{4}\cdot \vec A  + \frac{1}{4}\cdot \vec B

P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b

Location of Q

\overrightarrow{QM} = \frac{1}{2}\cdot \overrightarrow{PM}

\vec M - \vec Q = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec P

\vec Q = \frac{1}{2}\cdot \vec P - \frac{1}{2}\cdot \vec M

\vec Q = \frac{1}{2}\cdot \left(\frac{3}{4}\cdot \vec A + \frac{1}{4}\cdot \vec B\right) -\frac{1}{2}\cdot \left(\frac{1}{2}\cdot \vec A + \frac{1}{2}\cdot \vec B\right)

\vec Q = \frac{1}{8}\cdot \vec A -\frac{1}{8}\cdot \vec B

Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b

The coordinates of M, P and Q in terms of a and b are M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b, P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b and Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b, respectively.

We kindly invite to check this question on midpoints: brainly.com/question/4747771

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2(l+b) =perimeter of rectangle.

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3 years ago
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