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Hello!
To know how many grams of Ammonium Chloride ( a solid) you'll need to make 1.50 L of a 0,01 M solution you'll need to use the definition of molar concentration (M=mol/L) in the following way:
So, you'll need to dissolve 0,8023 g of Ammonium Chloride in 1,5 L of water to make this solution.
Have a nice day!
To know how many grams of Ammonium Chloride ( a solid) you'll need to make 1.50 L of a 0,01 M solution you'll need to use the definition of molar concentration (M=mol/L) in the following way:
So, you'll need to dissolve 0,8023 g of Ammonium Chloride in 1,5 L of water to make this solution.
Have a nice day!
<h3>Answer:</h3>
7.182K
<h3>Explanation:</h3>From the question we are given;
- Initial temperature, T1 = 275 K
- Final temperature, T2 = 395 K
- Initial volume, V1 = 5 L
We are required to calculate the final volume, V2
- Charles's law is the law that relates the volume of a gas and its temperature.
- It states that the volume of a fixed mass of a gas and its absolute temperature are directly proportional at a constant pressure.
- Therefore;
To calculate, V2 we rearrange the formula;
Therefore, the ending volume will be 7.182K