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3 years ago

What would be the mass percent of a NaOHsolution in which 11.6g of NaOHwere completely dissolved in 238.4g of water?

Chemistry

1 answer:

Snezhnost [94]3 years ago

4 0

Answer:

4.54 % NaOH

Explanation:

$\text{Mass percent} = \dfrac{\text{Mass of component}}{\text{Total mass}} \times 100 \, \%$

Data:

Mass of NaOH = 11.6 g

Mass of water = 38.4 g

Mass of solution = 250.0 g

Calculation:

$\text{Mass \% NaOH} = \dfrac{\text{11.6 g NaOH}}{\text{250 g solution}} \times 100 \% = \textbf{4.54 \% NaOH}$

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2 years ago

Given the reaction to 2NaOH + H2 SO4 â Na2 SO4 + 2H2 O, what is the total number of grams of NaOH needed to react completely wit

vfiekz [6]

Answer:

4 moles, 160 g

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

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The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

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So,

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Answer:

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3 years ago