1) D
2) B
3) A
Hope this helps! :)
A. 1 proton and 1 neutron
Answer:
500g because 300g is less dense than 500g its kinda like a weight
Explanation:
i
The first order rate law has the form: -d[A]/dt = k[A] where, A refers to cyclopropane. We integrate this expression in order to arrive at an equation that expresses concentration as a function of time. After integration, the first order rate equation becomes:
ln [A] = -kt + ln [A]_o, where,
k is the rate constant
t is the time of the reaction
[A] is the concentration of the species at the given time
[A]_o is the initial concentration of the species
For this problem, we simply substitute the known values to the equation as in:
ln[A] = -(6.7 x 10⁻⁴ s⁻¹)(644 s) + ln (1.33 M)
We then determine that the final concentration of cyclopropane after 644 s is 0.86 M.
<span>The answer is 2.519 × 10^4. Use the distributive property: a × x + b × x = (a + b) × x. If a = 4.659, b = 2.14, and x = 10^4, then 4.659 × 10^4 − 2.14 × 10^4 = (4.659 - 2.14) × 10^4. Now, subtract numbers in parenthesis: 4.659 × 10^4 − 2.14 × 10^4 = (4.659 - 2.14) × 10^4 = 2.519 × 10^4.Hope this helps. Let me know if you need additional help!</span>
