Tenemos.
Masa de la mesa = 20kg
Masa encima = 10kg
Masa total = 30kg
Area de cada pata = 20cm² = 20cm² * 1/10000cm² * 1m² =0,002m²
Presió(P)n que se ejerce sobre cada pata.
P =F/A
P = Masa por gravedad/A Masa = 30kg Gravedad =9,8m/s²
P =(30kg * 9,8m/s²)/0,002m²
P = 294kg * m/s²/0,002m² Pero kg *m/s² = Nw
P = 294Nw0,002m²
P = 147000 Nw/m² Pero Nw/m² = pa
p =1,47 * 10⁵ pa
Respuesta.
La presión que se ejerce sobre cada pata es de 1,47 * 10⁵pa
Answer: no
Explanation:
because the object is moving downwards so it will be called decceleration . which is the opposite of acceleration .
The frequency of a simple harmonic oscillator such as a spring-mass system is given by

where
k is the spring constant
m is the mass attached to the spring.
Re-arranging the formula, we get:

and since we know the constant of the spring:

and the frequency of oscillation:
f=1.00 Hz
we can find the value of the mass attached to it:
Answer: 161.3
I have a acellus too and got this question correct, so I hope this helps y’all out