A motorbike is traveling to the left with a speed of 27.0 m s 27.0 s m 27, point, 0, start fraction, start text, m, end text,
1 answer:
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<u>Answer:</u>
The final velocity of the two railroad cars is 1.09 m/s
<u>Explanation:</u>
Since we are given that the two cars lock together it shows that the collision is inelastic in nature. The final velocity due to inelastic collision is given by
where
V= Final velocity
M1= mass of the first object in kgs = 12000
M2= mas of the second object in kgs = 10000
V1= initial velocity of the first object in m/s = 2m/s
V2= initial velocity of the second object in m/s = 0 (given at rest)
Substituting the given values in the formula we get
V = 2×12000 + 0x100012000 + 10000= 2400022000= 1.09 m/s
Which is the final velocity of the two railroad cars
Explanation:
The weight of the car is equal to, ...........(1)
Where
m is the mass of car
g is the acceleration due to gravity
The normal or vertical component of the force is,
or
.............(2)
The horizontal component of the force is,
Taking ratio of equation (1) and (2) as :
or
Hence, this is the required solution.