1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
guapka [62]
3 years ago
9

5) What is the net force caused by the moon acting on earth when the moon is 3.86x10^8 m away? The moon has a mass of 7.46x10^23

kg.
6) what is the force due to gravity exerted by Jupiter on the planet Venus?
7) How much does the mass of Saturn pull Mars?
8) how much more is earths force of gravity on Pluto than Venus force of gravity on Pluto?

Thanks!

Physics
1 answer:
Dimas [21]3 years ago
3 0

Answers:

5) 1.99(10)^{21} N

6) 1.37(10)^{18} N

7) 1.64(10)^{21} N

8)  4.29(10)^{10} N more than Venus force of gravity on Pluto

Explanation:

According to Newton's law of Universal Gravitation, the force F exerted between two bodies of masses M and m  and separated by a distance R is equal to the product of their masses and inversely proportional to the square of the distance:

F=G\frac{Mm}{R^{2}} (1)

Where G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}} is the Gravitational Constant

This is the equation we will use to solve each question in this problem.

<h3>5) Gravitational force between Earth and Moon</h3>

In this case we have:

F_{earth-moon} is the gravitational force between Earth and Moon

M=5.97(10)^{24} kg is the mass of the Earth

m=7.46(10)^{23} kg is the mass of the Moon

R=3.86(10)^{8} m is the distance between Earth and Moon

Solving:

F_{earth-moon}=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(5.97(10)^{24} kg)(7.46(10)^{23} kg)}{(3.86(10)^{8} m)^{2}} (2)

F_{earth-moon}=1.99(10)^{21} N (3)

<h3>6) Gravitational force between Jupiter and Venus</h3>

Assuming for a moment that the planets are perfectly aligned and all are in the same orbital period, we can make a rough estimation of the distance between Jupiter and Venus, knowing the distance of each to the Sun:

distance between Sun and Jupiter - distance between Sun and Venus=distance between Jupiter and Venus=R_{jupiter-venus} (4)

R_{jupiter-venus}=778.3(10)^{9} m - 108(10)^{9} m=6.703(10)^{11} m (5)

Using this value in the Law of Universal Gravitation equation:

F_{jupiter-venus}=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(1.90(10)^{27} kg)(4.87(10)^{24} kg)}{(6.703(10)^{11} m)^{2}} (6)

F_{jupiter-venus}=1.37(10)^{18} N (7)

<h3>7) Gravitational force between Saturn and Mars</h3>

Using the same assumption we made in the prior question:

distance between Sun and Saturn - distance between Sun and Mars=distance between Saturn and Mars=R_{saturn-mars} (8)

R_{saturn-mars}=1427(10)^{9} m - 227.9(10)^{9} m=227.9(10)^{9} m (9)

Using this value in the Law of Universal Gravitation equation:

F_{saturn-mars}=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(1.989(10)^{30} kg)(6.42(10)^{23} kg)}{(227.9(10)^{9} m)^{2}} (10)

F_{saturn-mars}=1.64(10)^{21} N (11)

<h3>8) How much more is earths force of gravity on Pluto than Venus force of gravity on Pluto?</h3>

Firstly, we need to find F_{earth-pluto} and then find F_{venus-pluto} in order to find the difference.

<u>For F_{earth-pluto}:</u>

M=5.97(10)^{24} kg is the mass of the Earth

m=1.46(10)^{22} kg is the mass of Pluto

R_{earth-pluto}=5.7504(10)^{12} m is the distance between Earth and Pluto

F_{earth-pluto}=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(5.97(10)^{24} kg)(1.46(10)^{22} kg)}{(5.7504(10)^{12} m)^{2}} (12)

F_{earth-pluto}=1.759(10)^{11} N (13) Force between Earth and Pluto

<u></u>

<u>For F_{venus-pluto}:</u>

M=4.87(10)^{24} kg is the mass of Venus

m=1.46(10)^{22} kg is the mass of Pluto

R_{venus-pluto}=5.792(10)^{12} m is the distance between Venus and Pluto

F_{venus-pluto}=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(4.87(10)^{24} kg)1.46(10)^{22} kg)}{(5.792(10)^{12} m)^{2}} (14)

F_{venus-pluto}=1.33(10)^{11} N (15) Force between Venus and Pluto

Calculating the difference:

F_{earth-pluto}-F_{venus-pluto}=1.759(10)^{11} N-1.33(10)^{11} N

Finally:

F_{earth-pluto}-F_{venus-pluto}=4.29(10)^{10} N (16)

Hence:

Earths force of gravity on Pluto is 4.29(10)^{10} N than Venus force of gravity on Pluto.

You might be interested in
How much does the speed of a car increase if it accelerates
Nata [24]

Answer:

12.5 m/s

Explanation:

a = Δv / Δt

2.5 m/s² = Δv / 5 s

Δv = 12.5 m/s

4 0
3 years ago
A particle with a charge of 5 × 10–6 C and a mass of 20 g moves uniformly with a speed of 7 m/s in a circular orbit around a sta
creativ13 [48]

Answer:

r = 0.22m

Explanation:

To find the radius of the circular trajectory, you first take into account that the centripetal force of the charged particle, is equal to the electric force between the particle that is moving and the particle at the center of the orbit.

Then, you have:

F_c=F_e=ma_c      (1)

m: mass of the particle = 20g = 20*10-3 kg

ac: centripetal acceleration = ?

q: charge of the particle = 5*10^-6C

Fe: electric force between the charges

The electric force is given by:

F_e=k\frac{qq'}{r^2}             (2)

r: radius of the orbit

q': charge of the particle at the center of the orbit = -5*10^-6C

Furthermore, the centripetal acceleration is:

a_c=\frac{v^2}{r}                 (3)

v: speed of the particle = 7m/s

You replace the expressions (2) and (3) in the equation (1) and solve for r:

k\frac{qq'}{r^2}=m\frac{v^2}{r}\\\\r=\frac{kqq'}{mv^2}

Finally, you replace the values of all parameters in the previous expression:

r=\frac{(8.98*10^9Nm^2/C^2)(5*10^{-6}C)(5*10^{-6}C)}{(20*10^{-3}kg)(7m/s)^2}\\\\r=0.22m

The radius of the circular trajectory is 0.22m

5 0
3 years ago
You have a string with a mass of 0.0135 kg. You stretch the string with a force of 8.29 N, giving it a length of 1.83 m. Then yo
Sphinxa [80]

The wavelength of the standing wave at fourth harmonic is; λ = 0.985 m and the frequency of the wave at the calculated wavelength is; f = 36.84 Hz

Given Conditions:

mass of string; m = 0.0133 kg

Force on the string; F = 8.89 N

Length of string; L = 1.97 m

1. To find the wavelength at the fourth normal node.

At the fourth harmonic, there will be 2 nodes.

Thus, the wavelength will be;

λ = L/2

λ = 1.97/2

λ = 0.985 m

2. To find the velocity of the wave from the formula;

v = √(F/(m/L)

Plugging in the relevant values gives;

v = √(8.89/(0.0133/1.97)

v = 36.2876 m/s

Now, formula for frequency here is;

f = v/λ

f = 36.2876/0.985

f = 36.84 Hz

Read more about Harmonics of standing waves at; brainly.com/question/10274257

#SPJ4

7 0
1 year ago
A light bulb will glow when electrons flow through it. As the electron flow increases, the brightness increases as well. A stude
SIZIF [17.4K]

Answer:

Please find the answer in the explanation

Explanation:

Given that a light bulb will glow when electrons flow through it. As the electron flow increases, the brightness increases as well. A student hooks up two circuits containing three light bulbs in each circuit. In one circuit the lights are connected in series and in the other circuit the lights are hooked up in parallel.

If you could only see the lights in the circuit and the wires were covered up, how could you tell the type of circuit?

The type of the circuit can be determined if you loose or unscrew one light bulb, all other bulbs will be switched of if connected in series. But if the others remain on it is a parallel circuit.

5 0
3 years ago
Neutrons, protons, electrons are known as subatomic particles<br> explain why that is?
Alekssandra [29.7K]
<span>Particles that are smaller than the atom are called subatomic particles. The three main subatomic particles that form an atom are protons, neutrons, and electrons. The center of the atom is called the nucleus.</span>
5 0
3 years ago
Read 2 more answers
Other questions:
  • The bigclaw snapping shrimp shown in (Figure 1) is aptly named--it has one big claw that snaps shut with remarkable speed. The p
    13·1 answer
  • Help me!!!!!!!!!!!!!!!!!!!
    5·1 answer
  • Two samples of water are mixed together.
    6·1 answer
  • The half life of cobalt-60 is 5.3 years. If a certain rock currently contains 10.0g of cabals -60 how much cobalt-60 will remain
    9·1 answer
  • When running a 100 meter race Wyatt reaches his maximum speed when he is 40 meters from the starting line, and 7 seconds have el
    9·1 answer
  • If 1.4% of the mass of a human body is calcium, how many kilograms of calcium are there in a 195-pound man?
    15·2 answers
  • The gas sample has now returned to its original state of 1.00 atm, 20.0 ∘c, and 1.00 l. what will the pressure become if the tem
    13·1 answer
  • 1.A Radio station broadcasts modern song on medium wave 350 Hz every day at ten o’clock in the morning. The velocity of radio wa
    5·1 answer
  • Can someone answer all of the questions?
    15·2 answers
  • How many meters are there in 1865 cm
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!