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patriot [66]
2 years ago
11

A child is sliding on a sled at 1.6m/s to the right. You stop the sled by pushing on it for 0.60s in a direction opposite to its

motion. If the mass of the child and sled is 37kg , what is the magnitude of the average force you need to apply to stop the sled
Physics
1 answer:
ella [17]2 years ago
4 0

Answer:

F = 98.67 N

Explanation:

Given that,

The initial velocity of the sled, u = 1.6 m/s

The mass of the child and the sled is 37 kg

The sled stops pushing on it for 0.60s in a direction opposite to its motion.

We need to find the magnitude of the average force you need to apply to stop the sled.

Impulse = change in momentum

We have, v = 0

Ft=m(v-u)\\\\F=\dfrac{-mu}{t}\\\\F=\dfrac{-37\times 1.6}{0.6}\\\\F=-98.67\ N

So, the magnitude of the average force is 98.67 N.

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What is her velocity
fenix001 [56]
The speed of something in any given direction. 
7 0
2 years ago
Choose the statement(s) that is/are true about the ratio \frac{C_p}{C_v} C p C v for a gas? (Ii) This ratio is the same for all
Blababa [14]

Answer:

(i) false

(ii) true

(iii) true

(iv) false

Explanation:

(i) The ratio of Cp and Cv is not constant for all the gases. It is because the value of cp and Cv is different for monoatomic, diatomic and polyatomic gases.

So, this is false.

(ii) For monoatomic gas

Cp = 5R/2, Cv = 3R/2

So, thier ratio

Cp / Cv = 5 / 3 = 1.67

This statement is true.

(iii) for diatomic gases

Cp = 7R/2, Cv = 5R/2

Cp / Cv = 7 / 5 = 1.4

This statement is true.

(iv) It is false.

6 0
3 years ago
when approaching the front of an idling jet engine, the hazard area extends forward of the engine approximately
Dominik [7]

when approaching the front of an idling jet engine, the hazard area extends forward of the engine approximately 25 feet.

<h3>What impact, if any, would jet fuel and aviation gasoline have on a turbine engine?</h3>

Tetraethyl lead, which is present in gasoline, deposits itself on the turbine blades. Because jet fuel has a higher viscosity than aviation gasoline, it may retain impurities with greater ease.

Once the gasoline charge has been cleared, start the engine manually or with an electric starter while cutting the ignition and using the maximum throttle.

On the final approach, the aeroplane needs to be re-trimmed to account for the altered aerodynamic forces. A substantial nose-down tendency results from the airflow producing less lift on the wings and less downward force on the horizontal stabiliser due to the reduced power and slower velocity.

Learn more about turbine engine refer

brainly.com/question/807662

#SPJ4

7 0
1 year ago
Some hypothetical alloy is composed of 12.5 wt% of metal A and 87.5 wt% of metal B. If the densities of metals A and B are 4.27
densk [106]

Answer:

The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

Explanation:

Given that,

Weight of metal A = 12.5%

Weight of metal B = 87.5%

Length of unit cell = 0.395 nm

Density of A = 4.27 g/cm³

Density of B= 6.35 g/cm³

Weight of A = 61.4 g/mol

Weight of B = 125.7 g/mol

We need to calculate the density of the alloy

Using formula of density

\rho=n\times\dfrac{m}{V_{c}\times N_{A}}

n=\dfrac{\rho\timesV_{c}\times N}{m}....(I)

Where, n = number of atoms per unit cells

m = Mass of the alloy

V=Volume of the unit cell

N = Avogadro number

We calculate the density of alloy

\rho=\dfrac{1}{\dfrac{12.5}{4.27}+\dfrac{87.5}{6.35}}\times100

\rho=5.98

We calculate the mass of the alloy

m=\dfrac{1}{\dfrac{12.5}{61.4}+\dfrac{87.5}{125.7}}\times100

m=111.15

Put the value into the equation (I)

n=\dfrac{5.9855\times(0.395\times10^{-9}\times10^{2})^3\times6.023\times10^{23}}{111.15}

n=1.99\approx 2\ atoms/cell

Hence, The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

5 0
3 years ago
Compared to the weak nuclear force the electromagnetic force
Crazy boy [7]

Explanation:

Weak nuclear force:

The interaction between the subatomic particles is called weak nuclear force.

The weak nuclear force is one of the four fundamental forces.

The weak nuclear force is effective at very short distance.

The range and relative strength of weak nuclear force is 10⁻¹⁸ m and 10²⁵ with respect to gravitational force respectively

Deuterium is formed due to the fusion of protons and neutrons under the action the weak force.

Example : Beta decay

Electromagnetic force:  

The interaction between the charged particles is called electromagnetic force.

The electromagnetic force is one of the four fundamental forces.

The electromagnetic force is effective at long range distance.  

The range and relative strength of electromagnetic force is infinity and 10³⁶ with respect to gravitational force respectively

Example : light

8 0
2 years ago
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