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3 years ago

What type of nuclear energy involves splitting atoms

Chemistry

2 answers:

Yakvenalex [24]3 years ago

8 0

Answer:

nuclear fission

Explanation:

rewona [7]3 years ago

6 0

Nuclear fission-a nuclear reaction in which a heavy nucleus splits spontaneously or on impact with another particle, with the release of energy.

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According to the following electron structure, how many valence electrons do these fluorine atoms have? F= 1s12s22p5

ddd [48]

The highest sequence for this shell is the number 2, preceding both the s and p in the diagram. This means that the outermost shell is the second level shell. In this shell, there are 7 electrons, 2 in the 2s orbital and 5 in the 2p orbital.

As a side note (not sure if this is a typo), the electron structure for fluorine begins with a 1s2, not a 1s1.

6 0

3 years ago

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The two isotopes of chlorine are 35/17 cl and 37/17cl. which isotope is the most abundant

Natalka [10]

The most abundant is 35/17 Cl

explanation

This is because Chlorine 35/17 is the one close to the average atomic mass of chlorine which is 35.46 u making it to be the most abundant.

average atomic mass of chlorine is 35.46 + or- 0.02

7 0

3 years ago

How many grams of CaCl2would be dissolved in 1.0 L of a 0.10M<br> solution of CaCl2?

Goryan [66]

Mass of CaCl2=11g
I hope this one is help you

3 0

3 years ago

A chemical compound has a molecular weight of 89.05 g/mole. 1.400 grams of this compound underwent complete combustion under con

Nataly_w [17]

Answer:

$\Delta _{comb}H=-2,265\frac{kJ}{mol}$

Explanation:

Hello!

In this case, for such calorimetry problem, we can notice that the combustion of the compound releases the heat which causes the increase of the temperature by 11.95 °C, it means that we can write:

$Q _{comb}=-C_{calorimeter}\Delta T_{calorimeter}$

In such a way, we can compute the total released heat due to the combustion considering the calorimeter specific heat and the temperature raise:

$Q _{comb}=-2980\frac{J}{\°C} *11.95\°C\\\\Q _{comb}=-35,611J$

Next, we compute the molar heat of combustion of the compound by dividing by the moles, considering 1.400 g were combusted:

$n=1.400g*\frac{1mol}{89.05g} =0.01572mol$

Thus, we obtain:

$\Delta _{comb}H=\frac{Q_{comb}}{n}=\frac{-35,611J}{0.01572mol} \\\\\Delta _{comb}H=-2,265,331\frac{J}{mol}*\frac{1kJ}{1000J} \\\\\Delta _{comb}H=-2,265\frac{kJ}{mol}$

Best regards!

7 0

3 years ago

PLEASE HELP WILL GIVE BRAINLIEST

Phoenix [80]

Answer:

Coefficients represents no of moles while subscripts represent no of atoms.

5 0

3 years ago

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