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garri49 [273]
3 years ago
11

A seawall with an opening is used to dampen the tidal influence in a coastal area (and limit erosion). The seawall is 2.5 m long

(in the direction perpendicular to the page), the mean sea level on the sea side is 2.2 m above the centroid of the slot. The mean sea level on the land side of the wall is 1.4 m above the centroid of the slot. The sea side tide fluctuates +0.6 m, and the landward tide fluctuates +0.4 m.
The slot extends the entire length of the wall and is estimated to have a discharge coefficient of 0.80.


If the volume of seawater moving from the sea side to the land side of the wall is to be no more than 6 000 m' in 18 hours, what is the maximum allowable height of the slot?


Note: the discharge coefficient is the ratio of the actual flow rate over the predicted flow rate. It mostly accounts for the fact that the average velocity is different from the velocity.
Engineering
1 answer:
raketka [301]3 years ago
3 0

Answer:

The maximum allowable Height of the slot is 11.685mm

Explanation:

The explanation is attached. The approach used is Bernoulli's equation

Download pdf
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g If the rails are originally laid in contact, what is the stress in them on a summer day when their temperature is 31.0
Anettt [7]

A) The amount of space must be left between adjacent rails if they are just to touch on a summer day when their temperature is 31.0 °C is; 0.6048 cm

B) The stress in the rails on a summer day when their temperature is 31.0 °C is; 86.4 × 10⁶ Pa

<h3>Linear Thermal Expansion</h3>

We are given;

Length; L = 14 m

Initial Temperature; T_i = −5 °C

Final Temperature; T_f = 31 °C

The formula for Linear Thermal Expansion is;

ΔL = L_i * α * ΔT

where;

L_i is initial length

α is thermal expansion

ΔL is change in length

ΔT is change in temperature

Now, the thermal expansion of steel from online tables is α = 1.2 × 10⁻⁵ C⁻¹

Thus;

ΔL = 14 * 1.2 × 10⁻⁵  * (31 - (-5))

ΔL = 6.048 × 10⁻³ m = 0.6048 cm

The formula to get the stress is;

σ = Y * α  * ΔT

where;

Y is young's modulus of steel = 20 × 10¹⁰ Pa

α is thermal expansion

ΔT is change in temperature

Thus;

σ = 20 × 10¹⁰ × 1.2 × 10⁻⁵ × (31 - (-5))

σ = 86.4 × 10⁶ Pa

The complete question is;

Steel train rails are laid in 14.0-m long segments placed end to end. The rails are laid on a winter day when their temperature is −5 °C.

(a) How much space must be left between adjacent rails if they are just to touch on a summer day when their temperature is 31.0 °C?

(b) If the rails are originally laid in contact, what is the stress in them on a summer day when their temperature is 31.0 °C?

Read more about Linear Thermal Expansion at; brainly.com/question/6985348

4 0
2 years ago
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